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6840 degrees

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Q: What is the sum of the interior of a 40 gon?
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Interior angles of a 40-gon?

The sum of the interior angles of an n-gon is (n-2)*180 degrees. So, for a 40-gon, the sum of the interior angles would be 38*180 = 6840 degrees. If the 40-gon was not regular that is as far as you could go. But if it was a regular n-gon, then all its interior angles are equal, and each would be of 6840/40 = 171 degrees.


What is the sum of the interior angles of a 13-gon?

The sum of interior angle ( Sum-of-interior-angles-n-gon) of n-gon is:If we have a ,Then


For a convex 35-gon what is the sum of the measures of the interior angles?

the sum of the interior angles of a 35-gon.


Interior angles of a 30-gon?

180x28 is the sum of the interior angles in a 30- gon


What is the sum of interior angles of a convex 45-gon?

the sum of the interior angles of a convex 45-gon is 7740.


What is the sum of the interior of 30-gon?

The interior angles of a 30-gon add up to 5040 degrees


What is the sum of the interior angles of a 38-gon?

The sum of the interior angles of an n-gon is found by the formula: (n-2)*(180) degrees. So a 38-gon would have (38-2)*(180) degree sum for its interior angles, which equals 6,480 degrees.


What is the sum of each interior angles of a 19-gon?

The 19 interior angles of a 19-agon add up to 3060 degrees.


What is the sum of the measures of the interior angles of 11-gon?

The interior angles of an 11-gon add up to 1620 degrees


What is the sum of the interior angles of a 19-gon?

3060


What is the interior angle sum of a 60-gon?

10440


The sum of the interior angles of a 7-gon is?

900.