The interior angles of a 30-gon add up to 5040 degrees
The interior angles of an 11-gon add up to 1620 degrees
Sum of what aspect of a 20-gon: the length of its sides, its interior angles, its exterior angles, its apothems?
5940 degrees
If you mean the sum of its interior angles then it is 4140 degrees
The sum of the interior angles of an n-gon is (n-2)*180 degrees. So, for a 40-gon, the sum of the interior angles would be 38*180 = 6840 degrees. If the 40-gon was not regular that is as far as you could go. But if it was a regular n-gon, then all its interior angles are equal, and each would be of 6840/40 = 171 degrees.
The sum of interior angle ( Sum-of-interior-angles-n-gon) of n-gon is:If we have a ,Then
the sum of the interior angles of a 35-gon.
180x28 is the sum of the interior angles in a 30- gon
the sum of the interior angles of a convex 45-gon is 7740.
The interior angles of a 30-gon add up to 5040 degrees
The sum of the interior angles of an n-gon is found by the formula: (n-2)*(180) degrees. So a 38-gon would have (38-2)*(180) degree sum for its interior angles, which equals 6,480 degrees.
The 19 interior angles of a 19-agon add up to 3060 degrees.
3060
900.
2700
4,320