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The sum of the interior angles of an n-gon is (n-2)*180 degrees.
So, for a 40-gon, the sum of the interior angles would be 38*180 = 6840 degrees.
If the 40-gon was not regular that is as far as you could go. But if it was a regular n-gon, then all its interior angles are equal, and each would be of 6840/40 = 171 degrees.
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∙ 14y ago
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what is the total of interior angles in a nonagon?
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