The sum of the square of 6 and 8 can be calculated by squaring each number individually and then adding the results together. Therefore, the square of 6 is 6^2 = 36, and the square of 8 is 8^2 = 64. Adding these two results together gives us 36 + 64 = 100. Hence, the sum of the square of 6 and 8 is 100.
Sum = 36 Count = 6 Average = Sum/Count = 36/6 = 6
-6
sqrt(n) + 6
82 + 8 = 64 + 8 = 72
6 + 8 = 14 -6 + -8 = -14 -6 + 8 = 2 6 + -8 = -2
6
The sum of 8 and 6 is 14 (8+6)
The sum of -8 and 6 is -2
The sum of n and the sum of 8 and 6 can be represented as n + (8 + 6). Simplifying the expression within the parentheses first, we get n + 14. Therefore, the final expression representing the sum of n and the sum of 8 and 6 is n + 14.
6 zero in the sum of 1000 square
The sum of the numbers 8, 6, and 4, is 8 + 6 + 4 = 18.
There is no sequence of adds or subtracts of 5, 6, 8, 9, and 10 that sum to 1. Check it with this C++ code... for (int i=0; i<32; ++i) { int sum = 0; if (i&1) sum += 5; else sum -= 5; if (i&2) sum += 6; else sum -= 6; if (i&4) sum += 8; else sum -= 8; if (i&8) sum += 9; else sum -= 9; if (i&16) sum += 10; else sum -= 10; cout << i << " " << sum << endl; }
-6
Sum = 36 Count = 6 Average = Sum/Count = 36/6 = 6
10^2 = 6^2 + 8^2 ie 100 = 36 + 64
14
8