Oh, dude, the sum of the square of 6 and 8 is 36 + 64, which equals 100. So, like, if you square 6, you get 36, and if you square 8, you get 64. Add them together, and boom, you've got 100. Easy peasy lemon squeezy.
The sum of the square of 6 and 8 can be calculated by squaring each number individually and then adding the results together. Therefore, the square of 6 is 6^2 = 36, and the square of 8 is 8^2 = 64. Adding these two results together gives us 36 + 64 = 100. Hence, the sum of the square of 6 and 8 is 100.
Sum = 36 Count = 6 Average = Sum/Count = 36/6 = 6
-6
sqrt(n) + 6
82 + 8 = 64 + 8 = 72
6 + 8 = 14 -6 + -8 = -14 -6 + 8 = 2 6 + -8 = -2
6
The sum of 8 and 6 is 14 (8+6)
The sum of -8 and 6 is -2
The sum of n and the sum of 8 and 6 can be represented as n + (8 + 6). Simplifying the expression within the parentheses first, we get n + 14. Therefore, the final expression representing the sum of n and the sum of 8 and 6 is n + 14.
6 zero in the sum of 1000 square
The sum of the numbers 8, 6, and 4, is 8 + 6 + 4 = 18.
There is no sequence of adds or subtracts of 5, 6, 8, 9, and 10 that sum to 1. Check it with this C++ code... for (int i=0; i<32; ++i) { int sum = 0; if (i&1) sum += 5; else sum -= 5; if (i&2) sum += 6; else sum -= 6; if (i&4) sum += 8; else sum -= 8; if (i&8) sum += 9; else sum -= 9; if (i&16) sum += 10; else sum -= 10; cout << i << " " << sum << endl; }
-6
Sum = 36 Count = 6 Average = Sum/Count = 36/6 = 6
10^2 = 6^2 + 8^2 ie 100 = 36 + 64
4*4=16,1+6=7 5*5=25,2+5=7 6*6=36,3+6=9 7*7=49,4+9=13 8*8=64,6+4=10 9*9=81,8+1=9 so 9 square is 81 sum of these two digit is 9. 9 square is answer.
14