Oh, dude, the sum of the square of 6 and 8 is 36 + 64, which equals 100. So, like, if you square 6, you get 36, and if you square 8, you get 64. Add them together, and boom, you've got 100. Easy peasy lemon squeezy.
The square of the sum of 5 and 8 can be expressed mathematically as ((5 + 8)^2). First, you calculate the sum, which is 13, and then square that result. Thus, it translates to (13^2 = 169).
The sum of 8 and 6 is 14. Therefore, if you add this to ( n ), the total would be ( n + 14 ).
Sum = 36 Count = 6 Average = Sum/Count = 36/6 = 6
The sum of 6 plus 2 is 8.
-6
The sum of 8 and 6 is 14 (8+6)
6 zero in the sum of 1000 square
The sum of the numbers 8, 6, and 4, is 8 + 6 + 4 = 18.
There is no sequence of adds or subtracts of 5, 6, 8, 9, and 10 that sum to 1. Check it with this C++ code... for (int i=0; i<32; ++i) { int sum = 0; if (i&1) sum += 5; else sum -= 5; if (i&2) sum += 6; else sum -= 6; if (i&4) sum += 8; else sum -= 8; if (i&8) sum += 9; else sum -= 9; if (i&16) sum += 10; else sum -= 10; cout << i << " " << sum << endl; }
-6
4*4=16,1+6=7 5*5=25,2+5=7 6*6=36,3+6=9 7*7=49,4+9=13 8*8=64,6+4=10 9*9=81,8+1=9 so 9 square is 81 sum of these two digit is 9. 9 square is answer.
14
8*8=64 , 6+4=10, 64 is two digit number That's
-6
82 + 8 = 64 + 8 = 72
1^2 + 6^2 + 7^2 + 8^21 + 36 + 49 + 64 = 150
you need a common denominator, ie the sum 3/4 - 1/8, turn 3/4 into eighths = 6/8, then sum is 6/8 - 1/8 = 5/8