Watch closely:The sum of 'n' and '8' is written as (n + 8).
The sum of the interior angles of an n sided figure is (n-2)*180 degrees So for an 8 sided figure, the sum is 6*180 = 1080 degrees.
Let's denote the five consecutive numbers as n, n+1, n+2, n+3, and n+4. The sum of these numbers is given by n + (n+1) + (n+2) + (n+3) + (n+4) = 5n + 10 = 40. Solving for n, we get n = 6. Therefore, the five consecutive numbers are 6, 7, 8, 9, and 10.
This is simple algebra. Let the unknown number be n. Then the sum of this number and 8 = n + 8.
The average of a sequence of numbers is equal to Average(x1, ... , xi) = Sum(n, i = 1)[xi]/n Example: Find the average of 5, 6, 8, 12, 15, and 29. Average = Sum[5, 6, 8, 12, 15, 29]/6 Average = (5+6+8+12+15+29)/6 Average = 11
mn = 8 ( Product) m + n = 6 (Sum) Hence m = 6 - n Substitute (6 -n)n = 8 Multiply out the brackets 6n - n^(2) = 8 n^(2) - 6n + 8 = 0 It is now in quadratic form and will factor Hence ((n - 2)(n - 4) = 0 n = 2 & n = 4 So '2' & '4' are the two numbers. Verification 2 + 4 = 6 2 x 4 = 8
8
Watch closely:The sum of 'n' and '8' is written as (n + 8).
s= -8 + n, or s=n - 8, where s is the sum and n is the number
The sum of the interior angles of an n sided figure is (n-2)*180 degrees So for an 8 sided figure, the sum is 6*180 = 1080 degrees.
It is n + 6.
Let's denote the five consecutive numbers as n, n+1, n+2, n+3, and n+4. The sum of these numbers is given by n + (n+1) + (n+2) + (n+3) + (n+4) = 5n + 10 = 40. Solving for n, we get n = 6. Therefore, the five consecutive numbers are 6, 7, 8, 9, and 10.
Let 'n' represent any number, and 'S' represent sum. S = 5 + 2n
sum of interior angles = (n-2)180=1080 1080/180=n-2 6=n-2 8=n
1. start 2. sum=0 3. input n 3. for i=1 to n do 4. input x 5. sum=sum+x end of for (3) 6. avg=sum/n 7. output sum, avg 8. stop
This is simple algebra. Let the unknown number be n. Then the sum of this number and 8 = n + 8.
It is n + 6.