The sum of n and the sum of 8 and 6 can be represented as n + (8 + 6). Simplifying the expression within the parentheses first, we get n + 14. Therefore, the final expression representing the sum of n and the sum of 8 and 6 is n + 14.
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Watch closely:The sum of 'n' and '8' is written as (n + 8).
The sum of the interior angles of an n sided figure is (n-2)*180 degrees So for an 8 sided figure, the sum is 6*180 = 1080 degrees.
Let's denote the five consecutive numbers as n, n+1, n+2, n+3, and n+4. The sum of these numbers is given by n + (n+1) + (n+2) + (n+3) + (n+4) = 5n + 10 = 40. Solving for n, we get n = 6. Therefore, the five consecutive numbers are 6, 7, 8, 9, and 10.
This is simple algebra. Let the unknown number be n. Then the sum of this number and 8 = n + 8.
The average of a sequence of numbers is equal to Average(x1, ... , xi) = Sum(n, i = 1)[xi]/n Example: Find the average of 5, 6, 8, 12, 15, and 29. Average = Sum[5, 6, 8, 12, 15, 29]/6 Average = (5+6+8+12+15+29)/6 Average = 11