Oh, dude, you've got three consecutive odd integers adding up to 465? That's like a math puzzle trying to ruin your day. So, technically, the middle number is 155, and the other two are 153 and 157. Boom, problem solved.
There are three of them there.
465,000,000 is an integer. Mixed numbers are between integers greater than one.
20% of 465= 20% * 465= 0.2 * 465= 93
30% of 465= 30% * 465= 0.3 * 465= 139.5
Three hundred = 300 Sixteen tens = 160 5 ones = 5 Adding 300 + 160 + 5 = 465
Let the odd integers be , n, n+2 & n+4 Hence n + (n+2) + (n +4) = 471 Add LHS 3n + 6 = 471 Subtract '6' from both sides 3n = 465 Divide both sides by '3' n = 155 n + 2 = 157 n + 4 = 159 Hence the integers are 155,157 & 159.
The sum of the first 30 positive integers is: 465.
Let the number be represented by 'a' a+(a+1)+(a+2)+(a+3)+(a+4)=465 a+a+1+a+2+a+3+a+4=465 a+a+a+a+a+1+2+3+4=465 5a+10=465 5a=465-10 5a=455 5a/5=455/5 a=91 So if a=91 a+1=92 a+2=93 a+3=94 a+4=95
There are three of them there.
465,000,000 is an integer. Mixed numbers are between integers greater than one.
(First + last) multiplied by half the last, in this case 31 x 15 ie 465.
465.75 or 465 3/4
Three times with a remainder of ninety
20% of 465= 20% * 465= 0.2 * 465= 93
30% of 465= 30% * 465= 0.3 * 465= 139.5
Three hundred = 300 Sixteen tens = 160 5 ones = 5 Adding 300 + 160 + 5 = 465
465, 930, 1395 and keep adding 465 forever.