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Q: What is the sum of x2 3x - 6 and 2x2 3?
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Factor x3 plus 2x2 plus 3x plus 6?

x3 + 2x2 + 3x + 6 = x2(x + 2) + 3(x + 2) = (x + 2)(x2 + 3)


What are the factors of 3x3 plus 5x2-6x-10?

(3x + 5)(x2 - 2)


X2 plus 7x equals -2x2 plus 6?

x2+7x=-2x2+6 3x2+7x-6=0 (3x-2)(x+3)=0 3x-2=0 or x+3=0 x=2/3 or x=-3


How Do You Factor The Trinomial -2x3-2x2 12x?

-2x3-2x2+12x (-2)(x3+x2-6x) (-2x)(x2+x-6) (-2x)(x2+3x-2x-6) (-2x)((x)(x+3)-2(x+3)) (-2x)((x-2)(x+3)


Find the sum of the roots x2 plus 3x equals -2?

-3/2


What is the factorization of -2x3 - 2x2 plus 12x?

-2x3 - 2x2 + 12x = -2x(x2 + x - 6) = -2x(x2 - 2x + 3x - 6) = -2x[ x(x - 2) + 3(x - 2) ] = -2x(x + 3)(x - 2)


How do you factorise- x2-3x 2 equals?

assuming x*2-3x+2:factors of -3:-1,3 --> sum: 21,-3 --> sum: -2(x-1)(x+3)


What is the answer for x2 plus 3x-18 equals 0?

X2 + 3X - 18 = 0What two factors of - 18 add up to 3 ??(X - 3)(X + 6)============so, by the zero sum rule,X = 3X = - 6


Which of the binomials is a factor of this trinomal x2-13x 36?

(x -3)(2x2 + 3x - 4)


What is the factorization of this trinomial -2x3 plus 2x2 plus 12x?

-2x3 + 2x2 + 12x = -2x(x2 - x - 6) = -2x(x2 + 2x - 3x - 6) = -2x[ x(x + 2) - 3(x + 2) ] = -2x(x - 3)(x + 2)


How do you factor 2x squared plus 3x equals 3x minus 1 squared minus x squared?

If you mean 2x2 + 3x = (3x - 1)2 - x2 Then you can solve it this way: Expand: 2x2 + 3x = 9x2 - 6x + 1 - x2 Group like terms: 2x2 + 3x = 8x2 - 6x + 1 6x2 - 9x - 1 = 0 Complete the square: 6x2 - 9x = 1 x2 - 3x/2 = 1/6 x2 - 3x/2 + 9/16 = 1/6 + 9/16 (x - 3/4)2 = 8/48 + 27/48 (x - 3/4)2 = 35/48 Solve for x: x - 3/4 = ± √(35/48) x - 3/4 = ± √(35/3) / 4 x = 3/4 ± √(35/3) / 4 x = [3 ± √(35/3)] / 4 If you mean something else, then you'll need to be clearer with your question.


How do you factor x3 plus x2-3x-3?

x3 + x2 - 3x - 3 x(x2 + x - 3) - 3