x=5
1.6
The formula to sum a series of numbers is: sum = 1/2 x number_of_numbers x (first_number + last_number) So to sum the integers 5 to 500: From 5 to 500 there are 500 - 5 + 1 = 496 integers, so sum = 1/2 x 496 x (5 + 500) = 125240
3*(5+x) or 3(5+x)
To express the sum of four times the opposite of a number and -5, first define the number as ( x ). The opposite of ( x ) is ( -x ). Therefore, four times the opposite of ( x ) is ( 4(-x) ), which simplifies to ( -4x ). The sum of this and -5 can be written as ( -4x - 5 ).
12 x 5 = 60
1.6
0.8333
X+5
x+5=7 -5 -5 x=2
The formula to sum a series of numbers is: sum = 1/2 x number_of_numbers x (first_number + last_number) So to sum the integers 5 to 500: From 5 to 500 there are 500 - 5 + 1 = 496 integers, so sum = 1/2 x 496 x (5 + 500) = 125240
3*(5+x) or 3(5+x)
7+(x+5)
x=5/y=5
12 x 5 = 60
Sum(X) = 37 Sum(X2) = 289 Var(X) = Sum(X2) - sum(X)2/n = 289 - 37*37/5 = 15.20
3 x 5 x 5 x 5 x 7
5+12=17 x