0.8333
7+(x+5)
1 2/5
Sum(X) = 37 Sum(X2) = 289 Var(X) = Sum(X2) - sum(X)2/n = 289 - 37*37/5 = 15.20
5+12=17 x
x=5
x + 7
7(x+-5) with the distributive property you can reduce it to7x+7*57x+35 which is the answer.
1.6
There is no seven-digit number that has a sum of 5. The smallest seven-digit number is 1,000,000, which already has a sum greater than 5.
0.8333
X+5
The formula to sum a series of numbers is: sum = 1/2 x number_of_numbers x (first_number + last_number) So to sum the integers 5 to 500: From 5 to 500 there are 500 - 5 + 1 = 496 integers, so sum = 1/2 x 496 x (5 + 500) = 125240
7+xy
3*(5+x) or 3(5+x)
7+(x+5)
x=5/y=5