The supplement of an angle is found by subtracting the angle from 180 degrees. Therefore, the supplement of 40 degrees is 180 - 40, which equals 140 degrees.
40
supplement + angle = 180180 - angle = supplementangle = supplement + 40 = 180 - angle +40 = 220-angle2 x angle = 220angle = 110 degrees
Let the angle be ( x ) degrees. The supplement of the angle is ( 180 - x ) degrees. According to the problem, the angle is 40 degrees more than its supplement, leading to the equation ( x = (180 - x) + 40 ). Solving this gives ( 2x = 220 ), so ( x = 110 ) degrees. Therefore, the angle measures 110 degrees.
Supplemental angles add to 180° 180° - 43°40" = 136°20" ■
Suppose the supplement of the angle is x degrees. Then the angle is 180 - x degrees. Therefore the complement of the angle is 90 - (180 - x) degrees = x - 90 degrees. So 5*(x - 90) - 2*x = 40 Solve the above equation for x.
40
supplement + angle = 180180 - angle = supplementangle = supplement + 40 = 180 - angle +40 = 220-angle2 x angle = 220angle = 110 degrees
40 degrees ( 180 - 140 = 40 )
25
140
Let the angle be ( x ) degrees. The supplement of the angle is ( 180 - x ) degrees. According to the problem, the angle is 40 degrees more than its supplement, leading to the equation ( x = (180 - x) + 40 ). Solving this gives ( 2x = 220 ), so ( x = 110 ) degrees. Therefore, the angle measures 110 degrees.
Supplement of 130 deg = 180 - 130 = 50 deg Complement of 50 deg = 90 - 50 = 40 degrees
You would subtract 40 degrees from 180 degrees so it would look like this:180 degrees - 40 degrees = 140 degrees
A calcium carbonate supplement is 40% calcium, which is higher than any other calcium supplement.
Supplemental angles add to 180° 180° - 43°40" = 136°20" ■
the supplementary angle of 40degrees is140degrees 40+140=180[sum of two supplementary angles is 180]
Suppose the supplement of the angle is x degrees. Then the angle is 180 - x degrees. Therefore the complement of the angle is 90 - (180 - x) degrees = x - 90 degrees. So 5*(x - 90) - 2*x = 40 Solve the above equation for x.