40 degrees ( 180 - 140 = 40 )
Angle is x degrees. Then 2(180 - x) = 5(90 - x) + 30 360 - 2x = 450 - 5x + 30 3x = 120 x = 40 Check: supplement is 140, 2 x 140 = 280 complement is 50, 5 x 50 = 250 difference is 30 as required. QED
140
Since the interior angle measure of the regular polygon is 140⁰, its exterior angle measure is 180⁰ - 140⁰ = 40⁰. Since the sum of the exterior angle measures is 360⁰, the polygon has 360⁰/40⁰ = 9 sides.
You would subtract 40 degrees from 180 degrees so it would look like this:180 degrees - 40 degrees = 140 degrees
140
40-degrees 140-degrees
A 140 degree angle is about half way between a 90 degree angle, which has lines that are perpendicular to each other, and a 180 degree angle, which is a straight line. A 140 degree angle is an obtuse angle which has a line a little over half way between the 90 degree and 180 degree angles.
A 140 degree angle would be called an obtuse angle.
The supplement of an angle is found by subtracting the angle from 180 degrees. Therefore, the supplement of 40 degrees is 180 - 40, which equals 140 degrees.
60
Let the angle be ( x = 40^\circ ). The supplementary angle is ( 180^\circ - x = 140^\circ ). According to the problem, ( x ) is 40 degrees less than three times its supplementary angle, which can be expressed as ( x = 3(140) - 40 ). Solving this gives ( x = 420 - 40 = 380 ), which contradicts ( x = 40 ). Therefore, the angle cannot satisfy the given condition.
140 degrees
No angle can be complementary to a 140 degree angle, as the sum of complementary angles is 90 degrees. But angles which are supplementary to each other add together to form a 180 degree angle.
140 degrees
140
Angle is x degrees. Then 2(180 - x) = 5(90 - x) + 30 360 - 2x = 450 - 5x + 30 3x = 120 x = 40 Check: supplement is 140, 2 x 140 = 280 complement is 50, 5 x 50 = 250 difference is 30 as required. QED
The sum of the angles is 180 degrees in any triangle. So 180-140 is 40 and the third angle is 40 degrees.