Surface area of a ball or sphere = 4*pi*radius2
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Surface Area = 2 × Base Area + Base Perimeter × Length
Surface Area = 2 × Base Area + Base Perimeter × Length
Let r be the radius of the (base)ball. The surface area of a sphere = 4 * pi * r ^2 Therefore, the surface area of an ideal (base)ball = 4 * 3.14159 * 1.475^2 [in^2] = 27.34 [in^2] Note that I don't like to use the term baseball, because a baseball is not an ideal sphere. A baseball has markings and asperities. A perfect sphere does not.
True.
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