Surface Area = 2 × Base Area + Base Perimeter × Length
Surface Area = 2 × Base Area + Base Perimeter × Length
Let r be the radius of the (base)ball. The surface area of a sphere = 4 * pi * r ^2 Therefore, the surface area of an ideal (base)ball = 4 * 3.14159 * 1.475^2 [in^2] = 27.34 [in^2] Note that I don't like to use the term baseball, because a baseball is not an ideal sphere. A baseball has markings and asperities. A perfect sphere does not.
True.
The answer is TRUE.
Base * height is surface area or (bh)
Surface Area = 2 × Base Area + Base Perimeter × Length
Surface Area = 2 × Base Area + Base Perimeter × Length
Let r be the radius of the (base)ball. The surface area of a sphere = 4 * pi * r ^2 Therefore, the surface area of an ideal (base)ball = 4 * 3.14159 * 1.475^2 [in^2] = 27.34 [in^2] Note that I don't like to use the term baseball, because a baseball is not an ideal sphere. A baseball has markings and asperities. A perfect sphere does not.
It is not possible to answer the question because the shape of the base is not known. As a result the surface area of the base, and hence the total surface area cannot be calculated.
The surface area of a prism is the two bases and all the sides A = 2 *area of base + Perimeter of base * Height of prism.
True.
The answer is TRUE.
A sphere has no base, and since it has no base, it has only a surface area and no lateral area.
A sphere has no base, and since it has no base, it has only a surface area and no lateral area.
False...
The surface area of a prism = 2 × area of base + perimeter of base × H