You can't tell. It can be anything. A cylinder wth a circumference of 52 can have
any length. It could be 0.001 long, or it could be 35 million long, or less, or more,
or anything in between. All of these different cylinders could have the same
circumference, but they all have different surface areas.
The surface area is (circumference) x (length). So the surface area of your cylinder
is 52 for every 1.0 unit it is long.
Entire surface area = (2*pi*52)+(10*pi*8) = 408.407 square meters to 3 decimal places
Total surface area including the end caps:- (2*pi*52)+(10*pi*6) = 110*pi square cm
The surface area is 6*52 = 150 sq metres.
2*pi*r*h+2*pi*r2=2*pi*5*8+2*pi*52 = 130pi Which is approx 408.40704...... The surface area of each of the two ends is pir2. The surface area of the curved surface is 2pirh. pi = 3.1416 r = 5 h = 8 Plug the values into the formulas. Each end surface area = 3.1416 X 52 = 78.54 Area of both of the two ends combined = 78.54 X 2 = 157.08 Curved surface area = 2 X 3.1416 X 5 X 8 = 251.328 Add the ends surface areas and curved surface area 157.08 + 251.328 = 408 rounded to the nearest whole number.
a pool is a cylinder. the volume is the surface area times the depth. the surface area is pi ( 3.14) times the radius squared which in your case is 3.14 x 12 x12 =462 square feet. multiply the depth in feet 4 feet ( you don't fill it right to the top) =1848 cubic feet. there are 8 gallons in a cubic foot of water therefore you need 14,784 gallons of water to fill a 24 by 52 foot round pool
Entire surface area = (2*pi*52)+(10*pi*8) = 408.407 square meters to 3 decimal places
Total surface area including the end caps:- (2*pi*52)+(10*pi*6) = 110*pi square cm
Entire surface area = (2*pi*52)+(pi*10*15) = 628.319 square inches rounded to 3 decimal places
circumference of the circle = pi*52 cm
The circumference of a circle if the diameter is 52 is 163.4 units.
The surface area is 6*52 = 150 sq metres.
2*pi*r*h+2*pi*r2=2*pi*5*8+2*pi*52 = 130pi Which is approx 408.40704...... The surface area of each of the two ends is pir2. The surface area of the curved surface is 2pirh. pi = 3.1416 r = 5 h = 8 Plug the values into the formulas. Each end surface area = 3.1416 X 52 = 78.54 Area of both of the two ends combined = 78.54 X 2 = 157.08 Curved surface area = 2 X 3.1416 X 5 X 8 = 251.328 Add the ends surface areas and curved surface area 157.08 + 251.328 = 408 rounded to the nearest whole number.
Total surface area including the base = (2*pi*52)+(pi*52) = 235.619 square metres to 3 decimal places
Surface area of the sphere: 4*pi*52 = 100*pi square units
There are 6 equal surfaces in a cube, hence area of each surface is 52/6 = 26/3 = 8.666666666. Take the square root of 8.666666666 to get side which is 2.943920289
circumference or perimeter of the semi-circle = (diameter*pi)/2 + diameter
Lateral area = surface area of 4 sides of the cube = 4s2 = 4 x 52 = 100