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What is the surface area of a regular pyramid with side length 8 and slant height 9 the number of the side of the base is given by 3?
Such a pyramid cannot exist. If it is a regular pyramid with side length 8, its slant height MUST be less than 8. In fact, it is approx 6.39.
The volume of a regular pyramid with a square base of 8cm and a slant height of 5 cm?
The volume of a regular pyramid with a square base of 8cm and a slant height of 5 cm is: 64 cm3
In the equation for the lateral area of a regular pyramid one can replace the slant height with the altitude of the pyramid?
False
How do you find the surface area of a regular pyramid?
Surface Area= 1/2perimeter x slant height + B * * * * * Perimeter = perimeter of base. B = Area of base.
What is the lateral area and surface area of a regular square pyramid?
Lateral area: Twice the side of the square times the slant height. Surface area: The side of the square squared plus twice the side of the square times the slant height. a=side of square b=slant height L.A.=2(ab) S.A.=(a)(a)+(2(ab))
What is the surface area of a regular pyramid with side length 8 and slant height 9 the number of the side of the base is given by 3?
Such a pyramid cannot exist. If it is a regular pyramid with side length 8, its slant height MUST be less than 8. In fact, it is approx 6.39.
The volume of a regular pyramid with a square base of 8cm and a slant height of 5 cm?
The volume of a regular pyramid with a square base of 8cm and a slant height of 5 cm is: 64 cm3
What is the slant height VP in the regular pyramid below?
The answer is given below.
In the equation for the lateral area of a regular pyramid one can replace the slant height with the altitude of the pyramid?
False
How do you find the surface area of a regular pyramid?
Surface Area= 1/2perimeter x slant height + B * * * * * Perimeter = perimeter of base. B = Area of base.
What is the lateral area and surface area of a regular square pyramid?
Lateral area: Twice the side of the square times the slant height. Surface area: The side of the square squared plus twice the side of the square times the slant height. a=side of square b=slant height L.A.=2(ab) S.A.=(a)(a)+(2(ab))
What is the slant height of the pyramid Louvre in Paris?
slant height of the pyramid Louvre in Paris=28 meters
When you see a picture of a right pyramid with a regular polygon base how do you identify its height and its slant height?
Its vertical height is that of the perpendicular from the centre of the base to the apex; the slant height is the length of the sloping "corner" between two faces. The height of a regular pyramid is the vertical distance from the center of base to the top and is usually shown with a line perpendicular to the base, denoted with a right angle to the base. The slant height it the height of the lateral face (the triangles) from the edge of the base to the top of the pyramid. It is the height of the triangle, not the pyramid itself. The slant height will also be the hypotenuse of a right angle formed from the altitude of the pyramid and the distance from the center of the base to the edge.
Why is it helpful to know the slant height of a pyramid to find its surface area?
Knowing the slant height helps because it represents the height of the triangle that makes up each lateral face. So, the slant height helps you to find the surface area of each lateral face.
What is the surface area of the right square pyramid in square meters?
It depends on the dimensions of the base and the height (slant or vertical) of the pyramid.
What is the slant height of a pyramid that has all sides as equilateral triangles with sides of length of 9 cm and the surface area of the pyramid is 140.4 square cm?
The surface area of the pyramid is superfluous to calculating the slant height as the slant height is the height of the triangular side of the pyramid which can be worked out using Pythagoras on the side lengths of the equilateral triangle: side² = height² + (½side)² → height² = side² - ¼side² → height² = (1 - ¼)side² → height² = ¾side² → height = (√3)/2 side → slant height = (√3)/2 × 9cm = 4.5 × √3 cm ≈ 7.8 cm. ---------------------------- However, the surface area can be used as a check: 140.4 cm² ÷ (½ × 9 cm × 7.8 cm) = 140.4 cm² ÷ 35.1 cm² = 4 So the pyramid comprises 4 equilateral triangles - one for the base and 3 for the sides; it is a tetrahedron.
What is the surface area of a square pyramid when 4 is the side length and 13 as the slant height?
120
