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What would be the formula for the lateral area of a regular pyramid where the base is a square with perimeter p and s is the slant height?
LA = 1/2psnewtest3
How do you find lateral area of a regular square pyramid?
1/2(p)(sh) ~which means~ 1/2 x perimeter x slant height slant height= pathagorean theory= c squared= a squared+b squared
How do you find the slant height of a pyramid with a rectangular base?
If you make a line from the top of the pyramid to the center of the base, you have the height of the pyramid. This meets at the midsegment of a line going across the base. Since the height of a pyramid is perpendicular with the base, get this: the height, a line of 1/2 the length of the base, and the slant height form a right triangle. So, you can use the Pythagorean Theorem! For example, if the base length is 6 and the height of the pyramid is 4, then you can plug them into the Pythagorean Theorem (a squared + b squared = c squared, a and b being the legs of a right triangle and c being the hypotenuse). 1/2 the length of the base would be 6 divided by 2=3. 3 squared + 4 squared = slant height squared. 9+16=slant height squared. 25= slant height squared. Slant height=5 units. You're welcome!
What is the slant height of a square pyramid?
The slant height of a square pyramid is always perpendicular to the base. It is form the top vertex all the way down to the most center of one side of the base edge.
How do you find the slant height of a 6 sided pyramid?
if you know the height and the apothem, use pythagorean theorem to solve for it.
