The line of symmetry of y = 0 is x = 0.
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the line of symmetry would occur at x=0
For y - 2y - 3y equals 0, y equals 0.
a = 3 and y = 0
y = 3x^(2) + 24x - 1 Differentiate and equate to '0' dy/dx = 6x - 24 = 0 6x - 24 = 0 6x = 24 x = 4 is the line of symmetry.
x = y = 0 ?