the line of symmetry would occur at x=0
For y - 2y - 3y equals 0, y equals 0.
a = 3 and y = 0
x = y = 0 ?
The y-intercept equals 0.
the line of symmetry would occur at x=0
y2 = 32x y = ±√32x the vertex is (0, 0) and the axis of symmetry is x-axis or y = 0
axis of symmetry is x=0 Vertex is (0,0) So the answer is : YES
For y - 2y - 3y equals 0, y equals 0.
a = 3 and y = 0
x = y = 0 ?
The y-intercept equals 0.
y = 0x = y + 2plug 0 in for yx = 0 + 2x = 2
0
If: 3x+y = 4 and x+y = 0 Then: x = 2 and y = -2
Take the derivative: y' = 2x + 4. Set equal to zero: 2x + 4 = 0 --> x = -2. Substitute into original and y = -3. Axis of symmetry is x = -2. Vertex is (-2,-3)
Symmetry, which states that if A = B then B = A Put A = 4 and B = x + y