This is an arithmetic sequence with t1 = 1 and the common difference d = -18.
The nth term of an arithmetic sequence is given by the formula:
tn = t1 + (n - 1)d (substitute 10 for n, 1 for t1, and -18 for d)
t10 = 1 + (10 - 1)(-18) = 1 + 9(-18) = 1 - 162 = -161
Thus the 10th number of the sequence is -161.
35
-47, -41, -35, -29, -23, -17, -11, -5, 1, etc.
Find the next two number in the sequence
It is: nth term = 35-9n
35
35
The answer is 44. The sequence is adding nine to each number, assuming that the first number is supposed to be -1.
-47, -41, -35, -29, -23, -17, -11, -5, 1, etc.
17/35 is simplified because 17 is a prime number.
Chlorine-35 has 18 neutrons. Its atomic number is 17, which indicates the number of protons in the nucleus. By subtracting the atomic number from the mass number (35 - 17), we can determine the number of neutrons.
It is: 35
In the sequence 35, 70, 105, 140, 175, each number is the previous number plus 35.
Find the next two number in the sequence
The mass number of the chlorine atom would be 17 (number of protons) + 18 (number of neutrons) = 35. The atomic number, which is the number of protons, remains 17.
In an atom of chlorine with an atomic number of 17, the number of protons in the nucleus is 17. Since the atom is neutral, it will also have 17 electrons. Neutrons can be calculated by subtracting the atomic number from the atomic mass, so for chlorine with an atomic mass of 35, it would have 35 - 17 = 18 neutrons in the nucleus.
It is: nth term = 35-9n
35