It is: nth term = 35-9n
To find the nth term of a sequence, we first need to identify the pattern or rule governing the sequence. In this case, the sequence appears to be increasing by 9, then 13, then 17, and so on. This pattern indicates that the nth term is given by the formula n^2 + n - 1. So, the nth term of the sequence 0, 9, 22, 39, 60 is n^2 + n - 1.
The given sequence is an arithmetic sequence where each term increases by 4. The first term (a) is 13, and the common difference (d) is 4. The nth term can be found using the formula: ( a_n = a + (n-1)d ). Therefore, the nth term is ( a_n = 13 + (n-1) \cdot 4 = 4n + 9 ).
The sequence 5, 9, 13, 17 is an arithmetic sequence where each term increases by 4. The first term (a) is 5, and the common difference (d) is 4. The nth term can be expressed using the formula: ( a_n = a + (n-1)d ). Therefore, the nth term is given by ( a_n = 5 + (n-1) \cdot 4 = 4n + 1 ).
-11n + 17
To find the nth term of the sequence 9, 12, 17, 24, 33, we first look at the differences between consecutive terms: 3, 5, 7, and 9. These differences themselves increase by 2, indicating a quadratic relationship. We can derive the nth term formula as ( a_n = n^2 + 8n + 1 ). Thus, the nth term of the sequence can be expressed as ( a_n = n^2 + 8n + 1 ).
t(n) = 12*n + 5
It is 4n+5 and so the next term will be 25
To find the nth term of a sequence, we first need to identify the pattern or rule governing the sequence. In this case, the sequence appears to be increasing by 9, then 13, then 17, and so on. This pattern indicates that the nth term is given by the formula n^2 + n - 1. So, the nth term of the sequence 0, 9, 22, 39, 60 is n^2 + n - 1.
The given sequence is an arithmetic sequence with a common difference of 4 between each term. To find the nth term of an arithmetic sequence, we use the formula: nth term = a + (n-1)d, where a is the first term, d is the common difference, and n is the term number. In this case, the first term (a) is -3, the common difference (d) is 4, and the term number (n) is the position in the sequence. So, the nth term of the given sequence is -3 + (n-1)4 = 4n - 7.
The given sequence is an arithmetic sequence where each term increases by 4. The first term (a) is 13, and the common difference (d) is 4. The nth term can be found using the formula: ( a_n = a + (n-1)d ). Therefore, the nth term is ( a_n = 13 + (n-1) \cdot 4 = 4n + 9 ).
The nth term is 5n-3 and so the next term will be 22
-11n + 17
5
7n - 4
To find the nth term of the sequence 9, 12, 17, 24, 33, we first look at the differences between consecutive terms: 3, 5, 7, and 9. These differences themselves increase by 2, indicating a quadratic relationship. We can derive the nth term formula as ( a_n = n^2 + 8n + 1 ). Thus, the nth term of the sequence can be expressed as ( a_n = n^2 + 8n + 1 ).
The nth term in the arithmetic progression 10, 17, 25, 31, 38... will be equal to 7n + 3.
To find the nth term of this sequence, we first need to identify the pattern. The differences between consecutive terms are 5, 9, 13, 17, and so on. These are increasing by 4 each time. This means that the nth term can be calculated using the formula n^2 + 4n + 1. So, the nth term for the sequence 5, 10, 19, 32, 49 is n^2 + 4n + 1.