It would be 60 ml
Gay
1. Measure the length of one of the sides and cube it (ie multiply the length by the length by the length) 2. Get a bowl with enough water to cover the cube; mark the level of the water; submerge the cube in the water and mark the new level of the water. The volume of the cube is the volume between the two marks - this can be measured by removing the cube and using a measuring jug to measure the amount of water that is needed to be added to raise the water from the first mark to the second mark.
By its mass sweety. :) * * * * * It depends on the size of the rock. If you can lift it, find a container that is big enough to hold it. Put that container inside a collecting tray. Fill the container with water (or another liquid) to a level at least as high as the rock. Mark that level. Put the rock in the container gently. Measure the rise in the level of water and, if appropriate, collect the water that overflowed into the collecting tray. Calculate the difference in the two water levels. Add the overflow volume if appropriate. That sum is the volume of water displaced by the rock and so the volume of the rock. If the rock is too massive to lift or be contained in something you will need to estimate its volume. That can be done by profiling its shape and partitioning that into smaller, more regular shapes. Calculate the volumes of all those shapes and sum the answers.
The volume represented by each medium tick mark on a graduated cylinder depends on the total volume capacity of the cylinder and the number of divisions or increments marked on it. To determine the volume represented by each tick mark, you would divide the total volume capacity of the cylinder by the number of divisions marked on it. For example, if you have a 100 mL graduated cylinder with 10 equally spaced divisions, each medium tick mark would represent 10 mL of volume.
If it is for volume, then you first need a graduated cylinder. Put water in there, then put an object in there, and then mark and record the difference. If it is a 12 milliliter (mL) difference, then it is 12 cm3, since 1 mL = 1 cm3
Gay
the object volume is equal to the water displaced, or 10ml. Density is 15/10 = 1.5g/ml
The volume of the metal can be calculated by measuring the volume of water displaced after the metal was placed in the cylinder. If the water level rose to the 25 cubic meter mark after the metal was added, then the volume of the metal is 5 cubic meters.
1. Measure the length of one of the sides and cube it (ie multiply the length by the length by the length) 2. Get a bowl with enough water to cover the cube; mark the level of the water; submerge the cube in the water and mark the new level of the water. The volume of the cube is the volume between the two marks - this can be measured by removing the cube and using a measuring jug to measure the amount of water that is needed to be added to raise the water from the first mark to the second mark.
The easiest way to find the volume of irregular objects is to use water displacement Fill a beaker or other container with water and place the paper clip in the water. The amount the water level rises is the volume of the paper clip. Of course because a paper clip is so small you would either need to use highly accurate measuring devices or place enough paperclips in the water that there is a noticeable change in water level. you would then divide the change in water level by the number of paperclips you put in to get the average volume of a single paper clip.
Fill a cylindrical pool (a pool with vertical sides) with water and measure the level of water in it. Sumberge the human body and measure the level of water. Volume of body = increase in volume in pool = area of cross section of pool * increase in height of water. The pool need not be cylindrical, but being so makes the calculations simpler.
Reading the water volume at eye level ensures an accurate measurement by minimizing parallax error, which occurs when the water level appears higher or lower than it actually is due to the viewing angle. This technique helps to ensure precise readings and avoid miscalculations in volume measurements.
The volume of the stone is measured by displacement. Water is put into the measuring cylinder to a noted mark. The stone is placed in the cylinder and the water level will rise. The difference between the two levels is the volume in ml of the stone.
One way to calculate the density of an irregular object is to measure its mass using a scale. Next, you can calculate its volume by displacement method - submerge the object in water in a container and measure the volume of water displaced. Finally, divide the mass by the volume to find the density.
The volume of the stone is equal to the difference in water levels before and after the stone was added, so the volume of the stone is 85mL - 50mL = 35mL. To find the density, divide the mass of the stone (75.0g) by its volume (35mL). The density of the stone is 75.0g / 35mL ≈ 2.14 g/mL.
The answer depends on what the statue is made of. If it is made of clay, measuring its volume could be extremely difficult. If it is metal, you could immerse it into a giant graduated container of water. Mark the level of the water before and after the statue is immersed. The difference between the two is the volume of the statue - but only if either the statue is solid or that no water can get into it.
The Volume of the rock is 7-2=5 ML then the Density of the rock is 25g/5ml=5 g/ml