It is: 0.5*(10 squared - (3*10)) = 35 diagonals
A convex decagon has 10 sides. The formula for calculating the number of diagonals in a polygon is ( \frac{n(n-3)}{2} ), where ( n ) is the number of sides. For a decagon, substituting ( n = 10 ) gives ( \frac{10(10-3)}{2} = \frac{10 \times 7}{2} = 35 ). Therefore, a convex decagon has 35 diagonals.
decagon
35
A decagon has 10 sides and 35 diagonals
A decagon has 35 diagonals. This can be computed by multiplying ten by seven and dividing by two. Seven is derived from the number of sides minus three.
There are 35 diagonals in a 10 sided decagon
A convex decagon has 10 sides. The formula for calculating the number of diagonals in a polygon is ( \frac{n(n-3)}{2} ), where ( n ) is the number of sides. For a decagon, substituting ( n = 10 ) gives ( \frac{10(10-3)}{2} = \frac{10 \times 7}{2} = 35 ). Therefore, a convex decagon has 35 diagonals.
A tetra-decagon is a 14 sided polygon having 77 diagonals
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decagon
35.
35
35
A decagon has 10 sides and 35 diagonals
There are 5 sets of 3 parallel diagonals (where one is a major diagonal and 2 of them span 2 vertices. Each set makes 3 pairs, so there are 5 * 3 = 15 pairs. There are 5 sets of 4 parallel diagonals (where 2 of them span 1 vertex, and 2 of them span 3 vertices. Each set makes 6 pairs, so there are 5 * 6 = 30 pairs. So that's 15 + 30 = 45 pairs.
A decagon has 35 diagonals. This can be computed by multiplying ten by seven and dividing by two. Seven is derived from the number of sides minus three.
35 diagonals