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Factor the trinomial below 14x plus 29x-15?
Assuming you mean 14x2... (7x - 3)(2x + 5)
How do you factor 3x2 7x 6?
If that's +7x - 6, the answer is (x + 3)(3x - 2)
What are the factors of the following trinomial 2x2 plus 7x plus 3?
(2x + 1)(x + 3) are the factors.
What are the factors of 3x squared minus 7x plus 4?
The sum of the coefficients is 3 - 7 + 4 = 0 so (x - 1) is a factor. Thus, 3x2 - 7x + 4 = 3x2 - 3x - 4x + 4 = 3x(x - 1) - 4(x - 1) = (3x - 4)(x - 1)
How do you completely factor 21x4-14x3 plus 35x2 plus 7x?
7x(3x3 - 2x2 + 5x + 1)
Factor the trinomial 3x2 plus 7x-6?
3x2+7-6 = (3x-2)(x+3) when factored
What are the factors of the quadratic trinomial 3x2-7x plus 4?
3x2-7x+4 = (3x-4)(x-1) when factored
Factor the trinomial and enter your answer below Write each factor as a polynomial in descending order 3x2 - 7x - 20?
3x2-7x-20 = (3x+5)(x-4) when factored
What are the factors of this quadratic trinomial 3x2-7x plus 4?
(3x - 4)(x - 1)
What is the factor trinomial 2x plus 7x plus 10?
10 + 9x
What is the factor of 3x2 plus 7x-20?
(3x - 5)(x + 4)
Factor the trinomial negative x2 plus 7x plus 18?
-((x + 2)(x - 9))
How do you factor the trinomial -x2 plus 7x plus 18 with each factor as a polynomial in descending order?
-((x + 2)(x - 9))
How do you factor the trinomial 5x2 plus 7x plus 2 with each factor as a polynomial in descending order?
(5x + 2)(x + 1)
What is the factorization of the trinomial below 7x2 plus 7x - 14?
To factor the trinomial (7x^2 + 7x - 14), first factor out the common factor of 7: [ 7(x^2 + x - 2) ] Next, we can factor the quadratic (x^2 + x - 2) into ((x + 2)(x - 1)). Thus, the complete factorization of the original trinomial is: [ 7(x + 2)(x - 1) ]
Factor the polynomial 21x3-35x2 plus 14x?
21x3-35x2+14x = 7x(3x2-5x+2)
Factor the trinomial x2 plus 7x - 18 Enter each factor as a polynomial in descending order?
(X+9)(x-2)
