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What is the units digit of 2 to the 48th power?
Expressed in numerical form, 248 = 281474976710656 - the units digit is therefore 6. With the exception of 20 = 1. the units digit of successive powers of 2 runs 2, 4, 8, 6... continuously - therefore, an exponent which is a multiple of 4 will have a units digit of 6.
What is the units digit of 2 to the power of 2011?
To find the units digit of a number raised to a power, we can look for patterns in the units digits of the powers of that number. For 2, the units digits of the powers cycle in a pattern: 2, 4, 8, 6. Since 2011 is 3 more than a multiple of 4 (2011 = 4 * 502 + 3), the units digit of 2 to the power of 2011 will be the fourth number in the cycle, which is 6.
What is the units digit of 2 to the 725th power?
Look at the first few powers of 2: 2, 4, 8, 16, 32, 64, 128, 256,512, 1024, 2048The units digit repeats every four: [ 2 - 4 - 8 - 6 ] - [ 2 - 4 - 8 - 6 ] - etc.725/4 = 181 with remainder of 1 .So if you raise 2 to the 725th power, the units digit completes the whole4-step cycle [ 2-4-8-6 ] 181 times, and then advances one more step ... to 2 .
How can you tell what the ones digit of the product of 38 multipled by7will be without solving the whole problem?
Find the units digit of 8*7. The 30 in 38 will have no effect on the units digit.
What is last unit in 2 to the power of 1997?
The last digit of a number raised to a power can be determined by finding a pattern in the units digits of the number's powers. For 2 raised to the power of 1997, the units digit will follow a pattern of 2, 4, 8, 6. Since 1997 is one less than a multiple of 4, the last digit will be 8.
What is the units digit of 8 to the power of 50?
To find the units digit of 8 to the power of 50, we need to look for a pattern in the units digits of powers of 8. The units digit of powers of 8 cycles in a pattern: 8^1 = 8, 8^2 = 4, 8^3 = 2, 8^4 = 6, and so on. Since the cycle repeats every 4 powers, we can divide 50 by 4 to find that the 50th power will have the same units digit as 8^2, which is 4. Therefore, the units digit of 8 to the power of 50 is 4.
What is the unit’s digit in the expansion of 2 raised to 725?
The unit's digit in the expansion of 2 raised to the 725th power is 8. This can be determined by using the concept of the "unit's digit law". This law states that the units digit of a number raised to any power is the same as the units digit of the number itself. In this case, the number is 2, which has a units digit of 2, so the units digit of 2 to the 725th power is also 2. However, this is not the final answer. To get the unit's digit of 2 to the 725th power, we must use the "repeating pattern law". This law states that when a number is raised to any power, the unit's digit will follow a repeating pattern. For 2, this pattern is 8, 4, 2, 6. This means that the units digit of 2 to any power will follow this pattern, repeating every 4 powers. So, if we look at the 725th power of 2, we can see that it is in the 4th cycle of this repeating pattern. This means that the units digit of 2 to the 725th power is 8.
What is the units digit of 2 to the 48th power?
Expressed in numerical form, 248 = 281474976710656 - the units digit is therefore 6. With the exception of 20 = 1. the units digit of successive powers of 2 runs 2, 4, 8, 6... continuously - therefore, an exponent which is a multiple of 4 will have a units digit of 6.
What is the units digit of 2 to the power of 2011?
To find the units digit of a number raised to a power, we can look for patterns in the units digits of the powers of that number. For 2, the units digits of the powers cycle in a pattern: 2, 4, 8, 6. Since 2011 is 3 more than a multiple of 4 (2011 = 4 * 502 + 3), the units digit of 2 to the power of 2011 will be the fourth number in the cycle, which is 6.
What is the units digit of 248?
It is 8.
What is the value of the digit 8 in 68?
8 units
What value will the units digit of the number 20082008 be?
8 : the units digit is the first digit to the left of the decimal point if you had to write one in.
When is a number a multiple of 4?
When the tens digit is even and the units digit is 0, 4 or 8 or the tens digit is odd and the units digit is 2 or 6.
What is a two digit number that has a tens digit that is 8 more than the ones digit?
19?
What is the units digit of 2 to the 725th power?
Look at the first few powers of 2: 2, 4, 8, 16, 32, 64, 128, 256,512, 1024, 2048The units digit repeats every four: [ 2 - 4 - 8 - 6 ] - [ 2 - 4 - 8 - 6 ] - etc.725/4 = 181 with remainder of 1 .So if you raise 2 to the 725th power, the units digit completes the whole4-step cycle [ 2-4-8-6 ] 181 times, and then advances one more step ... to 2 .
How do you find the unit digit of 312 power 6?
Since neither the three hundred, nor the ten can contribute to the units digit in the answer, you look for a pattern in the units digit in the powers of 2n.20 = 121 = 222 = 423 = 824 = 2and after that , the pattern repeats, 4, 8, 2, 4, 8, 2, ...So if n (mod 3) = 1 the units digit is 2if n (mod 3) = 2 the units digit is 4and if n (mod 3) = 0 the units digit is 8where n (mod 3) is the remainder when n is divided by 3.312 is divisible by 3 [3+1+2=6 is divisible by 3] so 312 mod(3) =0 and so the units digit is 8.Since neither the three hundred, nor the ten can contribute to the units digit in the answer, you look for a pattern in the units digit in the powers of 2n.20 = 121 = 222 = 423 = 824 = 2and after that , the pattern repeats, 4, 8, 2, 4, 8, 2, ...So if n (mod 3) = 1 the units digit is 2if n (mod 3) = 2 the units digit is 4and if n (mod 3) = 0 the units digit is 8where n (mod 3) is the remainder when n is divided by 3.312 is divisible by 3 [3+1+2=6 is divisible by 3] so 312 mod(3) =0 and so the units digit is 8.Since neither the three hundred, nor the ten can contribute to the units digit in the answer, you look for a pattern in the units digit in the powers of 2n.20 = 121 = 222 = 423 = 824 = 2and after that , the pattern repeats, 4, 8, 2, 4, 8, 2, ...So if n (mod 3) = 1 the units digit is 2if n (mod 3) = 2 the units digit is 4and if n (mod 3) = 0 the units digit is 8where n (mod 3) is the remainder when n is divided by 3.312 is divisible by 3 [3+1+2=6 is divisible by 3] so 312 mod(3) =0 and so the units digit is 8.Since neither the three hundred, nor the ten can contribute to the units digit in the answer, you look for a pattern in the units digit in the powers of 2n.20 = 121 = 222 = 423 = 824 = 2and after that , the pattern repeats, 4, 8, 2, 4, 8, 2, ...So if n (mod 3) = 1 the units digit is 2if n (mod 3) = 2 the units digit is 4and if n (mod 3) = 0 the units digit is 8where n (mod 3) is the remainder when n is divided by 3.312 is divisible by 3 [3+1+2=6 is divisible by 3] so 312 mod(3) =0 and so the units digit is 8.
How can you tell what the ones digit of the product of 38 multipled by7will be without solving the whole problem?
Find the units digit of 8*7. The 30 in 38 will have no effect on the units digit.
