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This is an arithmetic progression with a first term of 1, a difference of 1, last term (and number of terms) 105.

→ sum = ½ × number_of_terms × (first_term + last_term)

= ½ × 105 × (1 + 105)

= ½ × 105 × 106

= 5565

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Q: What is the value of 1 plus 2 plus 3... plus 105?
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