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β 11y agoGiven: f(x) = 2x2 - 8x + 9 This function describes a parabola, which only has one extreme value. To find that value, you can take the derivative of the function, and use that to find the point at which it has a slope of zero: f'(x) = 4x - 8 if f'(x) = 0, then: 0 = 4x - 8 ∴4x = 8 ∴ x = 2 Now we work out the corresponding value for f(2): f(2) = 2(2)2 - 8(2) + 9 = 8 - 16 + 9 = 1 So the extreme value for this function is 1, which occurs at the point (2, 1)
4x2+4x-8 4(x2+x-2) and (4x+8)(x-1)
4x-8-2 can be more easily written as 4x-10. The solution to this equation would be 5/2
4x - 2y = 8 Rearrange into the 'straight line ' form of y = mx + c Hence -2y = -4x + 8 y = 2x - 4 The 'c' value is the y-intercept, which '-4' . The steepness/gradient of the slope is '2'.
(4x-8)2 = (4x-8)(4x-8) = 16x2-32x-32x+64 = 16x2-64x+64
3x + 8 = 4x + 23x - 4x = 2 - 8-x = -6x = 6
4x-5y = -8 4x+40 = y => y = 4x+40 Substitute the value of y into the top equation: 4x-5(4x+40) = -8 4x-20x-200 = -8 4x-20x = 200-8 -16x = 192 Divide both sides by -16 to find the value of x: x = -12 Substitute the value of x into the original equations to find the value of y: Therefore: x = -12 and y = -8
4X + 8 = 2 subtract 8 from both sides 4X + 8 - 8 = 2 - 8 4X = - 6 divide both sides by 4 X = -3/2 check 4(-3/2) + 8 = 2 -12/2 + 8 = 2 -6 + 8 = 2 2 = 2 checks
If: y = x -2 and 7y -4x = 10 Then: x = 8 and y = 6
-2
2X + 8^2 = 2X+64, for whatever value X. If the question is (2x+8)², the answer is 4x²+32x+64 The formula is (a+b)² = a² + 2ab + b². a=2x, b=8, a²=4x², b²=64
If 4x = 8, then x = 2
Presumably this is an equation in which the value of x is to be found. 7x+8 = 4x-10 7x-4x = -10-8 3x = -18 x = -6
change the equation around 4x-6=2 becomes 4x=2+6
x2 - 4x = 8 x2 - 4x + 4 = 8 + 4 (x - 2)2 = 12 x - 2 = +&- sq. root of 12 x = 2 +&- 2(sq. root of 3)
4x² - 30 = 34 4x² = 34 + 30 4x² = 64 4x = √64 4x = 8 x = 8 ÷ 4 x = 2
4x - 7 = -15 4x = -8 x = -2