The value of ( \frac{3^2}{3^4} ) can be simplified using the property of exponents that states ( \frac{a^m}{a^n} = a^{m-n} ). Therefore, ( \frac{3^2}{3^4} = 3^{2-4} = 3^{-2} ). This can be further expressed as ( \frac{1}{3^2} ), which equals ( \frac{1}{9} ). Thus, the final value is ( \frac{1}{9} ).
0.03 is the square power
48
I believe that the answer is 2 over 3
(2^5)/2 - (2^(3/2)) = 12
2 to the power of 2 over 3, or (2^{\frac{2}{3}}), can be expressed as the cube root of (2^2). This simplifies to (\sqrt[3]{4}), which is approximately (1.5874).
0.03 is the square power
48
I believe that the answer is 2 over 3
2/3
(2^5)/2 - (2^(3/2)) = 12
It is: 3^2 plus 2^3 = 17 meaning 9 plus 8 = 17
5
2 to the power of 2 over 3, or (2^{\frac{2}{3}}), can be expressed as the cube root of (2^2). This simplifies to (\sqrt[3]{4}), which is approximately (1.5874).
1.5
3+(2+8)^2÷4×1 over 2 to the power of 4(4 points)
28,832 to the power of 3/2 equals 4,895,670.204
Just 2 2 to power 3 is 2x2x2=8 2 to power 2 is 2x2=4 2 to power 1 is 2