To find the value of (3n + 1) when (n = 4), substitute 4 for (n):
[ 3(4) + 1 = 12 + 1 = 13. ]
Therefore, the value of (3n + 1) when (n = 4) is 13.
3n + 4 = 7(- 4 from both sides)3n = 3(divide both sides by 3)n = 1
-n + 4(n + 1) = 3n+4
-3n+5n+4 = -4 2n = -4-4 2n = -8 n = -4
To solve the equation (3n - 2 = 4(n + 3)), start by distributing the 4 on the right side: (3n - 2 = 4n + 12). Rearranging gives (3n - 4n = 12 + 2), which simplifies to (-n = 14). Thus, (n = -14).
3n2-8n+4 = (3n-2)(n-2) when factored
3n + 2 + (3n + 3 - 3n + 1) = 3n + 2 + (3n + 3 - 3n + 1) = 3n + 2 + (4) = 3n + 6
7n - 2 + 3n + 4 = 7n + 3n - 2 + 4 = 10n + 2 which can be simplified to 2(5n +1)
The answer to -2(4+3n)=24 is:-5.33
3n + 4 = 7(- 4 from both sides)3n = 3(divide both sides by 3)n = 1
3n+2+3n+2=6n+4
-n + 4(n + 1) = 3n+4
15n + 5 or 5(3n + 1)
Gather like terms. The - 2 and 4; the 7n and 3n. 7n - 2 + 3n + 4 = 10n + 2
-3n+5n+4 = -4 2n = -4-4 2n = -8 n = -4
-5(3n plus 4) 40 is a set of disjointed expressions: it is not a formula and so cannot be solved.
To solve the equation (3n - 2 = 4(n + 3)), start by distributing the 4 on the right side: (3n - 2 = 4n + 12). Rearranging gives (3n - 4n = 12 + 2), which simplifies to (-n = 14). Thus, (n = -14).
n=4