What is the value of 81x2y3 z if x3 y4 and z19?

Answer 1

Oh, what a delightful question! Let's paint a happy little equation together. If x equals 3, y equals 4, and z equals 19, then the value of 81x^2y^3z would be 81 * 3^2 * 4^3 * 19. Let's softly blend those numbers together and see the beautiful result unfold.

Answer 2

Well, honey, if x=3, y=4, and z=19, then 81x^2y^3z becomes 81(3)^2(4)^3(19), which simplifies to 81964*19. You do the math, and you get a whopping value of 743,136. So, there you have it, darling - the value of 81x^2y^3z when x=3, y=4, and z=19.

Answer 3

Oh, dude, let's break this down. So, if x equals 3, y equals 4, and z equals 19, then 81 times 2 times 3 to the power of 4 times 19 equals... math time... a whopping 69,696. Yeah, that's right. So, like, that's the value you're looking for. Math can be fun, right?

Answer 4

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