9p2 + 6 - 8 = 9p2 - 2
3x2x1=6 permutations.
There are 120 permutations and only 1 combination.
10! permutations of the word "Arithmetic" may be made.
There are 195 3-letter permutations.
9p2 + 6 - 8 = 9p2 - 2
Yes. 9p2 + 12pq + 4q2 = (3p + 2q)2
3x2x1=6 permutations.
There are 8! = 40320 permutations.
There are 6! = 720 permutations.
If you mean permutations of the letters in the word "obfuscation", the answer is 1,814,400.
There are 120 permutations and only 1 combination.
39916800 permutations are possible for the word INFORMATION.
10! permutations of the word "Arithmetic" may be made.
There are 195 3-letter permutations.
A freezer is a freezer: it has a fixed shape and a fixed purpose so there are really no permutations.
If there are n objects and you have to choose r objects then the number of permutations is (n!)/((n-r)!). For circular permutations if you have n objects then the number of circular permutations is (n-1)!