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What is the exact value of tan pie over 6?
1/sqrt(3)
What is the value of tan 75 degrees?
The value of tan 75 degrees can be calculated using the angle sum identity for tangent: tan(75°) = tan(45° + 30°) = (tan 45° + tan 30°) / (1 - tan 45° * tan 30°). Since tan 45° = 1 and tan 30° = 1/√3, substituting these values gives tan 75° = (1 + 1/√3) / (1 - 1/√3) = (√3 + 1) / (√3 - 1). Simplifying this expression results in tan 75° = 2 + √3.
What is the absolute value of negative 2 over 3?
I believe that the answer is 2 over 3
What is the exact value of tan 195?
The exact value of (\tan 195^\circ) can be found using the tangent addition formula. Since (195^\circ) is in the third quadrant, where tangent is positive, we can express it as (\tan(180^\circ + 15^\circ)). This gives us (\tan 195^\circ = \tan 15^\circ), which is (\frac{\sin 15^\circ}{\cos 15^\circ}). Using the known values, (\tan 15^\circ = 2 - \sqrt{3}). Therefore, (\tan 195^\circ = 2 - \sqrt{3}).
What is the value of tan 15 degree in fraction?
The value of ( \tan 15^\circ ) can be calculated using the tangent subtraction formula: [ \tan(15^\circ) = \tan(45^\circ - 30^\circ) = \frac{\tan 45^\circ - \tan 30^\circ}{1 + \tan 45^\circ \tan 30^\circ} ] Substituting the known values ( \tan 45^\circ = 1 ) and ( \tan 30^\circ = \frac{1}{\sqrt{3}} ), we find: [ \tan(15^\circ) = \frac{1 - \frac{1}{\sqrt{3}}}{1 + 1 \cdot \frac{1}{\sqrt{3}}} = \frac{\sqrt{3} - 1}{\sqrt{3} + 1} ] Thus, ( \tan 15^\circ = 2 - \sqrt{3} ) in its simplest fractional form.
What is the exact value of tan pie over 6?
1/sqrt(3)
What is the exact value of tan 105 degrees?
To find the exact value of tan 105°. First, of all, we note that sin 105° = cos 15°; and cos 105° = -sin 15°. Thus, tan 105° = -cot 15° = -1 / tan 15°. Using the formula tan(α - β) = (tan α - tan β) / (1 + tan α tan β); and using, also, the familiar values tan 45° = 1, and tan 30° = ½ / (½√3) = 1/√3 = ⅓√3; we have, tan 15° = (1 - ⅓√3) / (1 + ⅓√3); whence, cot 15° = (1 + ⅓√3) / (1 - ⅓√3) = (√3 + 1) / (√3 - 1) {multiplying through by √3} = (√3 + 1)2 / (√3 + 1)(√3 - 1) = (3 + 2√3 + 1) / (3 - 1) = (4 + 2√3) / 2 = 2 + √3. Therefore, tan 105° = -cot 15° = -2 - √3, which is the result we sought. We are asked the exact value of tan 105°, which we gave above. We can test the above result to 9 decimal places, say, by means of a calculator: -2 - √3 = -3.732050808; and tan 105° = -3.732050808; thus indicating that we have probably got the right result.
What is the value of tan 75 degrees?
The value of tan 75 degrees can be calculated using the angle sum identity for tangent: tan(75°) = tan(45° + 30°) = (tan 45° + tan 30°) / (1 - tan 45° * tan 30°). Since tan 45° = 1 and tan 30° = 1/√3, substituting these values gives tan 75° = (1 + 1/√3) / (1 - 1/√3) = (√3 + 1) / (√3 - 1). Simplifying this expression results in tan 75° = 2 + √3.
What is the exact value of tan -60?
tan(-60 degrees) = - sqrt(3)
What is the exact trigonometric function value of cot 15 degrees?
cot(15)=1/tan(15) Let us find tan(15) tan(15)=tan(45-30) tan(a-b) = (tan(a)-tan(b))/(1+tan(a)tan(b)) tan(45-30)= (tan(45)-tan(30))/(1+tan(45)tan(30)) substitute tan(45)=1 and tan(30)=1/√3 into the equation. tan(45-30) = (1- 1/√3) / (1+1/√3) =(√3-1)/(√3+1) The exact value of cot(15) is the reciprocal of the above which is: (√3+1) /(√3-1)
What is the absolute value of negative 2 over 3?
I believe that the answer is 2 over 3
What is the exact value of tan 195?
The exact value of (\tan 195^\circ) can be found using the tangent addition formula. Since (195^\circ) is in the third quadrant, where tangent is positive, we can express it as (\tan(180^\circ + 15^\circ)). This gives us (\tan 195^\circ = \tan 15^\circ), which is (\frac{\sin 15^\circ}{\cos 15^\circ}). Using the known values, (\tan 15^\circ = 2 - \sqrt{3}). Therefore, (\tan 195^\circ = 2 - \sqrt{3}).
Which is greater tan 1tan2 tan3 .arrange them in descending order?
If the angles are measured in degrees or gradians, then: tan 3 > tan 2 > tan 1 If the angles are measured in radians, then: tan 1 > tan 3 > tan 2.
What is the absolute value of 2 over 3 in fractions?
2/3
What is the value of tan 15 degree in fraction?
The value of ( \tan 15^\circ ) can be calculated using the tangent subtraction formula: [ \tan(15^\circ) = \tan(45^\circ - 30^\circ) = \frac{\tan 45^\circ - \tan 30^\circ}{1 + \tan 45^\circ \tan 30^\circ} ] Substituting the known values ( \tan 45^\circ = 1 ) and ( \tan 30^\circ = \frac{1}{\sqrt{3}} ), we find: [ \tan(15^\circ) = \frac{1 - \frac{1}{\sqrt{3}}}{1 + 1 \cdot \frac{1}{\sqrt{3}}} = \frac{\sqrt{3} - 1}{\sqrt{3} + 1} ] Thus, ( \tan 15^\circ = 2 - \sqrt{3} ) in its simplest fractional form.
What is the value of 3 over 2?
1.5
What is 2 tan 30?
To find ( 2 \tan 30^\circ ), first recall that ( \tan 30^\circ = \frac{1}{\sqrt{3}} ). Thus, ( 2 \tan 30^\circ = 2 \times \frac{1}{\sqrt{3}} = \frac{2}{\sqrt{3}} ). This can also be rationalized to ( \frac{2\sqrt{3}}{3} ).
