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Q: What is the value of f(x) 2 2 x for f(2)?

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fx=3x-5 f=(3x-5)/x f2=(6x-10)/x /=divide

That depends what the function is! Just replace every occurrence of "x" by "x-2", and do any required simplifications.

y = f(x) = (x-5)2. At x = 5, the y value is zero, so the point (5,0).

Are you trying to solve for x? Fx = x2 - 3 x2 - Fx - 3 = 0 x2 - Fx = 3 x2 - Fx + (F/2)2 = 3 + (F/2)2 (x - F/2)2 = 3 + (F/2)2 x - F/2 = ±[ 3 + (F/2)2 ]1/2 x = F/2 ± [ 3 + (F/2)2 ]1/2

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fx=3x-5 f=(3x-5)/x f2=(6x-10)/x /=divide

That depends what the function is! Just replace every occurrence of "x" by "x-2", and do any required simplifications.

At x = 3, the value of F(x) = 3x + 2 is the value 11, which graphs to the point (3, 11).

y = f(x) = (x-5)2. At x = 5, the y value is zero, so the point (5,0).

Are you trying to solve for x? Fx = x2 - 3 x2 - Fx - 3 = 0 x2 - Fx = 3 x2 - Fx + (F/2)2 = 3 + (F/2)2 (x - F/2)2 = 3 + (F/2)2 x - F/2 = ±[ 3 + (F/2)2 ]1/2 x = F/2 ± [ 3 + (F/2)2 ]1/2

3

g(x) = x/2

You replace x with 1, and 36 times 1 = 36.

f(71.19) = 71 where int(x) is the integer value of a number

1 mole F2 = 37.996g F2 = 6.022 x 1023 molecules F2 85g F2 x 6.022 x 1023 molecules F2/37.996g F2 = 1.3 x 1024 molecules F2

The function f(x) = 3x + 2 can take any real value, so the question does not seem to make any sense.

It depends on whether fx denotes frequency times variable value or the probability generating function for the variable x.