Points: (1, 2) and (9, 6)
Midpoint: (5, 4)
Slope: 1/2
Perpendicular slope: -2
Perpendicular bisector equation: y-4 = -2(x-5) => y = -2x+14
Therefore: k = -2 thus satisfying the given bisector equation
As there is no change in y, the perpendicular bisector is given by x = (10 + k)/2 This is given as x = 7; thus: → (10 + k)/2 = 7 → 10 + k = 14 → k = 4
7x + 10y = 4.5 : 10y = -7x + 4.5 : y = -x.7/10 + 0.45, the gradient of this line is -7/10 Two straight lines are perpendicular if the product of their gradients is -1. Let the equation for the perpendicular line be y = mx + c Then m x -7/10 = -1 : m = 10/7 The equation for the perpendicular line is y = x.10/7 + c If the values of x and y for the point of intersection are provided then these can be substituted in the perpendicular line equation and the value of c obtained. If appropriate, the equation can then be restructured to a format similar to the original equation.
It is an equation and the value of a is 7
To find the value of "what" in the equation "what - what equals 477," we can set it up as "x - x = 477." However, since any number minus itself equals zero, there is no value of "what" that satisfies this equation. Therefore, the equation is not solvable in standard arithmetic.
It is an equation and the value of x is 2
As there is no change in y, the perpendicular bisector is given by x = (10 + k)/2 This is given as x = 7; thus: → (10 + k)/2 = 7 → 10 + k = 14 → k = 4
If a line has equation y = mx + c, the perpendicular line has gradient -1/m A line perpendicular to 3x + y = 2 has equation 3y = x + c; the value for c will be determined by a point through which the line must pass.
7x + 10y = 4.5 : 10y = -7x + 4.5 : y = -x.7/10 + 0.45, the gradient of this line is -7/10 Two straight lines are perpendicular if the product of their gradients is -1. Let the equation for the perpendicular line be y = mx + c Then m x -7/10 = -1 : m = 10/7 The equation for the perpendicular line is y = x.10/7 + c If the values of x and y for the point of intersection are provided then these can be substituted in the perpendicular line equation and the value of c obtained. If appropriate, the equation can then be restructured to a format similar to the original equation.
It is an equation and the value of a is 7
To find the value of "what" in the equation "what - what equals 477," we can set it up as "x - x = 477." However, since any number minus itself equals zero, there is no value of "what" that satisfies this equation. Therefore, the equation is not solvable in standard arithmetic.
6The line of best fit has the equation = -3 + 2.5x. What does this equation predict for a value of x = 3?Answer: 4.5
43
40
a = Zero
x = 9
It is an equation and the value of n is 9.1
It is an equation and the value of n is 14