7x + 10y = 4.5 : 10y = -7x + 4.5 : y = -x.7/10 + 0.45, the gradient of this line is -7/10
Two straight lines are perpendicular if the product of their gradients is -1.
Let the equation for the perpendicular line be y = mx + c
Then m x -7/10 = -1 : m = 10/7
The equation for the perpendicular line is y = x.10/7 + c
If the values of x and y for the point of intersection are provided then these can be substituted in the perpendicular line equation and the value of c obtained.
If appropriate, the equation can then be restructured to a format similar to the original equation.
-- The slope of the graph of [ 4x + y = 2 ] is -4.-- The slopes of perpendicular lines are negative reciprocals.-- The slope of any line perpendicular to [ 4x + y = 2 ] is 1/4 .
No, the two lines are not perpendicular.
It is a straight line with gradient -A/B and intercept C/B.
Slope of given line = -3 Therefore, slope of perpendicular = 1/3
The second equation works out as y = -1/2x+6 therefore it is perpendicular
+ 1/8
-- The slope of the graph of [ 4x + y = 2 ] is -4.-- The slopes of perpendicular lines are negative reciprocals.-- The slope of any line perpendicular to [ 4x + y = 2 ] is 1/4 .
The slope of the perpendicular is -(1/2) .
4x+5y = 7 5y = -4x+7 y = -4/5x+7/5 in slope intercept form So the slope of the perpendicular line is plus 5/4
No, the two lines are not perpendicular.
It is a straight line with gradient -A/B and intercept C/B.
10 is.
Slope of given line = -3 Therefore, slope of perpendicular = 1/3
negative 1
It is: 1/5
The second equation works out as y = -1/2x+6 therefore it is perpendicular
For the line 2x + y = 8 , the slope equals ( -2 ) so the required slope of the line which is perpendicular to it is equal to (+1/2 )