square root of -1
Yes, but it involves the square root of -1. sqrt (-X) = sqrt (X) * sqrt(-1)
value for root 3 is 1.732
sin75 = sin(45 + 30) = sin45cos30 + cos45sin30 = (1/root 2)((root 3)/2) + (1/root 2)(1/2)
1
square root of -1
1 or -1, but 1 is generally the accepted answer.
Yes, but it involves the square root of -1. sqrt (-X) = sqrt (X) * sqrt(-1)
a root number is a number in which satifies the unknown value of an equation. For example: x² - 1 = 0 the root of this equation would be 1 or -1 since when multiplied by itself, they both equal 1. Therefore, 1 - 1 = 0
value for root 3 is 1.732
Yes. The letter i denotes the value of the "positive square root" of -1. So i² = -1. But also (-i)² = -1 as well. Remember that for every number there is a "positive" and "negative" square root. So if you want the square root of -4, you can do this: -4 = (-1)(4). So sqrt(-4) = sqrt[(-1)(4)] = sqrt(-1)*sqrt(4) = i*2 or -i*2. We usually write these as 2i and -2i.
0.5
The value of (\sqrt{2} \times \sqrt{2}) is equal to 2, as the square root of a number multiplied by itself cancels out the square root and leaves the number. There is no concept of multiplying by infinity in this context as infinity is not a specific number but rather a concept representing unboundedness.
the squared root
You mean the value of the root node? Yes, we can.
sin75 = sin(45 + 30) = sin45cos30 + cos45sin30 = (1/root 2)((root 3)/2) + (1/root 2)(1/2)
Root 2 or 2^(1/2) is an irrational number. It is approximately 1.414214