answersLogoWhite

0

It is denoted by i, and is called the imaginary square root of -1.

User Avatar

Wiki User

14y ago

What else can I help you with?

Related Questions

What is the value of 1 divided by the square root of 2?

The value of 1 divided by the square root of 2 is approximately 0.707.


What is the value of 1 plus the square root of 2?

The value of 1 plus the square root of 2 is approximately 2.41.


What is the value of iota?

square root of -1


What is the value of square root of one?

1 or -1, but 1 is generally the accepted answer.


Can a value in a square root be negative?

Yes, but it involves the square root of -1. sqrt (-X) = sqrt (X) * sqrt(-1)


What is the value for root 3?

value for root 3 is 1.732


What is a root number in an equation?

a root number is a number in which satifies the unknown value of an equation. For example: x² - 1 = 0 the root of this equation would be 1 or -1 since when multiplied by itself, they both equal 1. Therefore, 1 - 1 = 0


The square root of a negative value is called an imaginary or number?

Yes. The letter i denotes the value of the "positive square root" of -1. So i² = -1. But also (-i)² = -1 as well. Remember that for every number there is a "positive" and "negative" square root. So if you want the square root of -4, you can do this: -4 = (-1)(4). So sqrt(-4) = sqrt[(-1)(4)] = sqrt(-1)*sqrt(4) = i*2 or -i*2. We usually write these as 2i and -2i.


Why the value of square root is 1divided by 2?

0.5


What is the value of square root?

the squared root


Can we change the root value of binary tree?

You mean the value of the root node? Yes, we can.


What is the value of square root of 2 square root of 2 .infinite?

The value of (\sqrt{2} \times \sqrt{2}) is equal to 2, as the square root of a number multiplied by itself cancels out the square root and leaves the number. There is no concept of multiplying by infinity in this context as infinity is not a specific number but rather a concept representing unboundedness.