Place value is the category the number the digit is in. For example, take 123. The 1 is worth one hundred, the 2 is worth 20 and the 3 is worth 3. Actual value is the number itself in that position. So, as an example, "What digit is in the hundreds place of the number 123?" The answer would be 1.
1 x 123, 3 x 41
If you meant 123, the mean of one number is itself. If you meant 1,2 and 3, you add the numbers and divide by the number of numbers, so (1+2+3)/(1+1+1) = 6/3 = 2
It means that in a number such as "123", each digit has a different value, due to its position. The 1 actually means 1 x 100, the 2 means 2 times 10, and the 3 means 3 x 1. The powers of 10 I listed (100, 10, and 1) are the "place value".
123 is not a multiple of 6 but 6 is. When an even whole number is multiplied by any other whole number the result is always an even number. 6 is an even number, 123 is an odd numbers; therefore 123 cannot be a multiple of 6. 6 = 6 × 1; therefore 6 is a multiples of 6.
Place value is the category the number the digit is in. For example, take 123. The 1 is worth one hundred, the 2 is worth 20 and the 3 is worth 3. Actual value is the number itself in that position. So, as an example, "What digit is in the hundreds place of the number 123?" The answer would be 1.
Well, honey, to change 123 to a fraction, you just put it over 1, so it becomes 123/1. Voila, you've got yourself a fraction! But seriously, that's as simple as it gets.
123.
Only the number 1 goes into both 43 & 123... because 43 is a prime number.
1 x 123, 3 x 41
123 can be written as a fraction: 123= 123/1
123 is not a prime number because it is divisible by 41 and 3. (123/41=3 and 123/3=41)A prime number is any number that is only divisible by two factors, one and itself.123 is a composite number because its factors are 1, 3, 41, and 123.
123 is a composite number because it is divisible by 3. A prime number has only 2 factors which are 1 and itself. Composite numbers are everything else except 1, 2, and 0. 1, 2, and 0 have a different name.
It is 123/1.123, as a fraction is 123/1.
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Let a be the first number and b the second number then, (1) a = 8 + 2b and (2) a + b =123 From (2) a = 123 - b substituting for a in (1) gives :- 123 - b = 8 + 2b , 3b = 115, b = 115/3 = 38⅓. and substituting for this in (2) gives :- a + 38⅓ = 123, a = 123 - 38⅓ = 84⅔. So, a = 84⅔ and b = 38⅓
If you meant 123, the mean of one number is itself. If you meant 1,2 and 3, you add the numbers and divide by the number of numbers, so (1+2+3)/(1+1+1) = 6/3 = 2