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The minimum value of the secant and cosecant is ' 1 '. There are no zeros.
The common term for this value is a quadrillion.
2,068,027
Yes it is. The trailing zeros have no affect on the value.
For a parabola in a normal position ... with its nose either straight up or straight down ... the x-value of the vertex is midway between the zeros of the function, i.e. their average.