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2.224
The normal distribution is symmetric about its mean; it increases from an asymptote with the x-axis below the mean until the mean whereupon it decreases until another asymptote with the x-axis the same distance above the mean. (This is not a linear increase/decrease, but a "bell" shape.) As the distribution is symmetric about its mean, only tables up to the mean need be calculated/given in a table. The area under the curve between any two points can then be calculated. For a normal distribution with mean µ and standard deviation σ, a z value is calculated for a given point x: z = (x - µ) / σ This z value is then used to look up the area in the given "half" tables, giving the area (probability) of the value lying between the mean and the given z value. If negative, z is below the mean, but for the table, the sign is ignored. This can be expressed as: area = normal(|z|) where normal(z) is the value in the normal table at the given (positive) z value. To calculate the area between two points (ie the probability that a value lies between two given values), their corresponding z values (z₁ and z₂) are first calculated and then combined viz: If they are both on the same side of the mean (ie z₁ and z₂ have the same sign) then the area is given by:area = | normal(|z₁|) - normal(|z₂|) | If they are on opposite sides of the mean (ie z₁ and z₂ have different signs) then the area is given by:area = normal(|z₁|) + normal(|z₂|) Almost all of the normal distribution lies between ±4 standard deviations of the mean.
97.61%
z value=0.44
z = 0.6903
Since the normal distribution is symmetric, the area between -z and 0 must be the same as the area between 0 and z. Using this fact, you can simplify this problem to finding a z such that the area between 0 and z is .754/2=.377. If you look this value up in a z-table or use the invNorm on a calculator, you will find that the required value of z will be 1.16. Therefore, the area between -1.16 and 1.16 must be approximately .754.
The question does not specify what z is but this answer will assume that it is the value of a random variable with a Standard Normal distribution. That being the case, the area under the curve between those values is 0.4875.
The area is 0.9270, approx.
There cannot be such a value since the total area, being a probability, is 1.
Charts typically show and list the area to the left of the Z-Score value. To find the area to the right, just subtract the Z-Score value from 1; e.g. if the Z-Score value is .75 then take 1-.75 = .25.
2.224
The Z value is 0.
0.97
It is 1.17
What is the area under the normal curve between z equals 0.0 and z equals 2.0?
They refer to the same thing as do z-transformations.
z = ±0.44