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What else can I help you with?
What Z value corresponds to a confidence level of 88 percent?
1.555 With 88% confidence, there is 6% (0.06) in either tail of the standard Normal distribution. Table C will not help here. Using Table A the correct z* is about halfway between 1.55 and 1.56. According to technology, z*=1.555
What percent of data falls between 1 Standard deviation below and 2 stand deviations above the mean?
The answer will depend on what the distribution is. Non-statisticians often assum that the variable that they are interested in follows the Standard Normal distribution. This assumption must be justified. If that is the case then the answer is 81.9%
What z score corresponds to 40 percent between the mean and the z?
z = 1.28, approx.
What value corresponds to the 38 percent of the data between the mean and the z value?
The value is 0.3055
What z value corresponds to 17 percent of the data between the mean and the z value?
I believe your question is to find a range going from the mean to a z-value on the standard normal distribution that corresponds to 17% of the area. A normal distribution goes from values of minus infinity to positive infinity. A standard normal distribution has a mean of 0 and an standard deviation of 1. It is usually best if you draw a diagram, in this case a bell shape curve with mean = 0. The area to the left of the mean is 50% of the total area. We find a z value that corresponds to 67% (50% + 17%) of the area to the left of this value. This can be done either with a lookup table or a spreadsheet program. I prefer excel, +norminv(0.67) = 0.44. The problem could also be worded to find the area going from a z-value to the mean. In this case, we must find a z-value that corrsponds to 33% (50-17). Using Excel, I calculate +norminv(0.33) = -0.44.
What Z value corresponds to a confidence level of 88 percent?
1.555 With 88% confidence, there is 6% (0.06) in either tail of the standard Normal distribution. Table C will not help here. Using Table A the correct z* is about halfway between 1.55 and 1.56. According to technology, z*=1.555
What letter grade is 90 percent on a test?
A 90 percent on a test typically corresponds to an "A-" grade, assuming standard grading scales.
What percent of data falls between 1 Standard deviation below and 2 stand deviations above the mean?
The answer will depend on what the distribution is. Non-statisticians often assum that the variable that they are interested in follows the Standard Normal distribution. This assumption must be justified. If that is the case then the answer is 81.9%
What percent of the scores in a normal distribution will fall within one standard deviation?
It is 68.3%
In a standard normal distribution 95 percent of the data is within plus standard deviations of the mean?
95% is within 2 standard deviations of the mean.
In a standard normal distribution about percent of the scores fall above a z-score of 3.00?
0.13
The standard z-score such that 80 percent of the distribution is below to the left of this value is?
z = 0.8416
What value corresponds to the 38 percent of the data between the mean and the z value?
The value is 0.3055
What z score corresponds to 40 percent between the mean and the z?
z = 1.28, approx.
How many standard deviations is needed to capture 75 percent of data?
It depends on the shape of the distribution. For standard normal distribution, a two tailed range would be from -1.15 sd to + 1.15 sd.
How many standard deviations are 95 percent of measurements away from the mean?
95 percent of measurements are less than 2 standard deviations away from the mean, assuming a normal distribution.
What z value corresponds to 17 percent of the data between the mean and the z value?
I believe your question is to find a range going from the mean to a z-value on the standard normal distribution that corresponds to 17% of the area. A normal distribution goes from values of minus infinity to positive infinity. A standard normal distribution has a mean of 0 and an standard deviation of 1. It is usually best if you draw a diagram, in this case a bell shape curve with mean = 0. The area to the left of the mean is 50% of the total area. We find a z value that corresponds to 67% (50% + 17%) of the area to the left of this value. This can be done either with a lookup table or a spreadsheet program. I prefer excel, +norminv(0.67) = 0.44. The problem could also be worded to find the area going from a z-value to the mean. In this case, we must find a z-value that corrsponds to 33% (50-17). Using Excel, I calculate +norminv(0.33) = -0.44.
