When alpha is 2 or less than 2 the variance of the inverse gamma doesn't exist. That is why when the variance is defined for the inverse gamma it always says "for α > 2". It is also the case that when alpha is 1 or less the mean of the inverse gamma doesn't exist. In order to really undertand what it means to say the variance doesn't exist (or the mean doesn't exist) you need to understand the mathematical definition of the variance (and of the mean). I don't know how to add the necessary symbols to clearly explain this. However, just briefly, mathematically both the mean and variance of the gamma density are definite integrals over the support of the density, which is 0 to infinity. In general, sometimes a definity integral over an infinite range (negative and/or positive) exists and sometimes it doesn't. In the case of the definite integral for the variance on the inverse gamma, when alpha less than or equal to 2, this integral doesn't exist.
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Yes.For some tests, such as the Fisher F-test, the test statistic is an estimate of the variance. If the alpha level was not affected, the test would be no use at all!Yes.For some tests, such as the Fisher F-test, the test statistic is an estimate of the variance. If the alpha level was not affected, the test would be no use at all!Yes.For some tests, such as the Fisher F-test, the test statistic is an estimate of the variance. If the alpha level was not affected, the test would be no use at all!Yes.For some tests, such as the Fisher F-test, the test statistic is an estimate of the variance. If the alpha level was not affected, the test would be no use at all!
(From Wolfram alpha)
The number 0 (zero) is the alpha and the omega when it comes to neutrality. It always was, is, and always will be neutral. 0 (zero) is neither positive nor negative. Thus, the additive or negative inverse of 0 (zero) is 0 (zero).
9410 + 5490 = 14900
A*sin(x) + cos(x) = 1B*sin(x) - cos(x) = 1Add the two equations: A*sin(x) + B*sin(x) = 2(A+B)*sin(x) = 2sin(x) = 2/(A+B)x = arcsin{2/(A+B)}That is the main solution. There may be others: depending on the range for x.