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average velocity = miles/hours = (100 + 30)/(2 + 1) = 130/3 ≈ 43.33 miles/hour
Average speed = Total Distance/Total Time = (15+25)/2 = 40/2 = 20 miles per hour. Velocity (due North) = Total NET distance North/Total Time = (15-25)/2 = -10/2 = -5 miles per hour or, velocity due South = 5 miles per hour.
25 miles.
10 miles per hour speed is not a vector quantity, therefore direction does not matter. 16 miles/ 2 hours=8 mph 24 miles/ 2 hours=12 mph (8+12)/2=10 mph average
Yes. Velocity is a vector and therefore requires magnitude and direction: Magnitude: 100 kph Direction: North
Speed = Distance divided by Time. So, speed = 75 miles divided by 2.5 hours = 75 / 2.5 = 30 miles per hour. Velocity is speed and direction, so the velocity is 30 mph Northbound.
average velocity = miles/hours = (100 + 30)/(2 + 1) = 130/3 ≈ 43.33 miles/hour
The car's net displacement is 0 miles (north 50 miles - south 50 miles). Since the total time taken is 5 hours, the velocity is 0 mph because velocity is displacement divided by time, resulting in 0 mph.
The velocity of the car is 65 miles per hour. This is calculated by dividing the distance traveled (260 miles) by the time taken (4 hours). Since direction is not specified in the calculation of velocity, the northeast direction does not affect the final answer.
Average speed = Total Distance/Total Time = (15+25)/2 = 40/2 = 20 miles per hour. Velocity (due North) = Total NET distance North/Total Time = (15-25)/2 = -10/2 = -5 miles per hour or, velocity due South = 5 miles per hour.
Velocity = 790.514 m/s North (rounded)The idea is to divide the distance by the time.
Yes. Velocity is a vector and therefore requires magnitude and direction: Magnitude: 100 kph Direction: North
25 miles.
10 miles per hour speed is not a vector quantity, therefore direction does not matter. 16 miles/ 2 hours=8 mph 24 miles/ 2 hours=12 mph (8+12)/2=10 mph average
3.00 m/s
30 miles per hour north
5 miles