0
0.0002315 m/s OR 0.0008333 km/hour
The velocity of an object is the rate of its change in position in a certain direction.
Velocity is a vector quantity; this means that it has both a magnitude and direction.
To find the average velocity of an object in motion, the following equation is used:
average velocity= (total displacement)/ (total time elapsed)
The SI units of velocity are "m/s" , but any distance unit over any time unit is also acceptable.
Solving for the velocity asked for:
First let's change hours to seconds:
(12 hours ) x (6o minutes/hour )x (60 seconds/minute)= 43200 seconds
Finding the velocity:
average velocity= (displacement)/ (time)= 10m/ 43200 seconds= 0.000231481 m/s
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∙ 14y ago
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How do you scale a quantity?
i think you mean a scaler quantity. a scaler quantity is something that is measured without a directional component to it. ie. mass, temperature, speed it could be negative value but the negative means its value. you can use a scale to measure scaler quantity. then there is vector quantities which have a direction to it. ie. velocity because something like velocity is 10m/s east OR -10m/s here the negative it is not a value but a direction (if 10m/s is to the right then -10m/s is to the left) don't confuse this with speed because speed is scaler it is just magnitude or value only. velocity is the displacement over time so it have a direction aswell. hope this helps
9h-6 plus 12h plus 40 equals 22?
-9-6+12h+40=22
What is h -9h-6 plus 12h plus 40 equals 22?
h-9h-6+12h+40 = 22 h-9h+12h = 22+6-40 4h = -12 h = -3
What is the answer to this algebra question 12h - 17 - h plus 16 - 2h?
12h-17-h+16-2h =12h-3h-17+16 =9h-1,if you mean the value of h,then h =1/9
A car having an initial velocity of 12 m per s east slows uniformly to 2 m per s east in 4 s What is the acceleration of the car in this interval?
12m/s-2m/s=10m/s 10m/s in 4s = 10m/s/4s=10/4 m/s^s = 2.5m/s^2 west
How can an object have a velocity of 0 m per s but still be accelerating?
^velocity* Consider an object that is travelling south at 10m/s. It accelerates north until it is travelling 10m/s. If we define south as negative, then it accelerates from -10m/s to 10m/s. -10 < 0 < 10, hence, it is travelling at 0m/s at some point.
Simplify 12h plus 5h?
It is: 12h+5h = 17h
How do you scale a quantity?
i think you mean a scaler quantity. a scaler quantity is something that is measured without a directional component to it. ie. mass, temperature, speed it could be negative value but the negative means its value. you can use a scale to measure scaler quantity. then there is vector quantities which have a direction to it. ie. velocity because something like velocity is 10m/s east OR -10m/s here the negative it is not a value but a direction (if 10m/s is to the right then -10m/s is to the left) don't confuse this with speed because speed is scaler it is just magnitude or value only. velocity is the displacement over time so it have a direction aswell. hope this helps
How do you find the velocity of an object that has fallen 10 m?
To find the velocity of an object that has fallen 10m, you can use the formula v = sqrt(2gh), where v is the velocity, g is the acceleration due to gravity (9.81 m/s^2), and h is the height the object has fallen (10m). Substituting the values, you find v = sqrt(2 * 9.81 m/s^2 * 10m) ≈ 14 m/s.
-9h-6 plus 12h plus 40 equals 22?
-9h-6+12h+40=22
9h-6 plus 12h plus 40 equals 22?
-9-6+12h+40=22
Solve this equation negative9h-6 plus 12h plus 40 equals 22?
-9h-6+12h+40=22 -9h+12h=22-40+6 3h=-12 h=-4
How tall is Mount Porcupine?
10M 10M 10M
20kg mass falls 10m what is maximum velocity?
The maximum velocity can be found using the equation v = sqrt(2gh), where v is the velocity, g is the acceleration due to gravity (9.8 m/s^2), and h is the height (10m). Plugging in the values, v = sqrt(29.810) = 14 m/s.
What is the answer to this algebra question 12h - 17 - h plus 16 - 2h?
12h-17-h+16-2h =12h-3h-17+16 =9h-1,if you mean the value of h,then h =1/9
What is h -9h-6 plus 12h plus 40 equals 22?
h-9h-6+12h+40 = 22 h-9h+12h = 22+6-40 4h = -12 h = -3
A car having an initial velocity of 12 m per s east slows uniformly to 2 m per s east in 4 s What is the acceleration of the car in this interval?
12m/s-2m/s=10m/s 10m/s in 4s = 10m/s/4s=10/4 m/s^s = 2.5m/s^2 west
