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To write the equation ( y^2 = x^2 + 16x + 17 ) in vertex form, we first complete the square for the ( x ) terms. The expression ( x^2 + 16x ) can be rewritten as ( (x + 8)^2 - 64 ). Thus, the equation becomes ( y^2 = (x + 8)^2 - 64 + 17 ), simplifying to ( y^2 = (x + 8)^2 - 47 ). Therefore, the vertex form of the equation is ( y^2 = (x + 8)^2 - 47 ).
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The vertex form of the equation of a parabola is y 4(x - 2)2 - 1. What is the standard form of the equation?
To convert the vertex form ( y = 4(x - 2)^2 - 1 ) to standard form, expand the equation. Start by expanding ( (x - 2)^2 ) to get ( x^2 - 4x + 4 ). Then, substitute this back into the equation: ( y = 4(x^2 - 4x + 4) - 1 ), which simplifies to ( y = 4x^2 - 16x + 16 - 1 ). Therefore, the standard form is ( y = 4x^2 - 16x + 15 ).
How do you find the vertex of the parabola y equals -4x2 - 16x - 11?
You would convert it to vertex form by completing the square. You can also find the optimum value as optimum value and vertex are the same.
Which equation represents a parabola opening to the right with a vertex at the origin and a focus at (40)?
The equation that represents a parabola opening to the right with its vertex at the origin (0,0) and a focus at (4,0) is given by ( y^2 = 4px ), where ( p ) is the distance from the vertex to the focus. Since the focus is located at (4,0), ( p = 4 ). Therefore, the equation of the parabola is ( y^2 = 16x ).
How many solutions are in the set 16x plus 2 - 8 equals 16x plus 24?
16x + 2 - 8 = 16x + 24 implies 16x - 6 = 16x + 24 subtracting 16x from both sides, this implies: -6 = 24 So the equation has no soultions.
X2 plus 16x plus 55 equals?
Assuming you wish to make this equation equal zero, for x2 + 16x + 55 = 0, x = -5.
The vertex form of the equation of a parabola is y 4(x - 2)2 - 1. What is the standard form of the equation?
To convert the vertex form ( y = 4(x - 2)^2 - 1 ) to standard form, expand the equation. Start by expanding ( (x - 2)^2 ) to get ( x^2 - 4x + 4 ). Then, substitute this back into the equation: ( y = 4(x^2 - 4x + 4) - 1 ), which simplifies to ( y = 4x^2 - 16x + 16 - 1 ). Therefore, the standard form is ( y = 4x^2 - 16x + 15 ).
How do you find the vertex of the parabola y equals -4x2 - 16x - 11?
You would convert it to vertex form by completing the square. You can also find the optimum value as optimum value and vertex are the same.
Which equation represents a parabola opening to the right with a vertex at the origin and a focus at (40)?
The equation that represents a parabola opening to the right with its vertex at the origin (0,0) and a focus at (4,0) is given by ( y^2 = 4px ), where ( p ) is the distance from the vertex to the focus. Since the focus is located at (4,0), ( p = 4 ). Therefore, the equation of the parabola is ( y^2 = 16x ).
Rewrite the equation 4x 4y20 in slope intercept form?
y = 16X - 80
What is 16x 3/5?
16x + 2 - 8 = 16x + 24 implies 16x - 6 = 16x + 24 subtracting 16x from both sides, this implies: -6 = 24 So the equation has no soultions.
What is the vertex of the graph -2x2 16x -15?
Considering a general quadratic equation y=ax^2 + bx + c, the x coordinate of the vertex is found from the formula x= -b/2a and the y coordinate is found from putting that x coordinate back into the original quadratic equation which in this case I am assuming is y= -2x^2 + 16x -15. So, the x coordinate of the vertex is x=-16/(2*-2) = 4 To find the y coordinate we plug 4 back into y= -2x^2 + 16x -15 so we have y= -2 * 4^2 + 16*4 - 15. Following the order of operations we get y= -2 *16 + 64 - 15= 17 Therefore the vertex is at (4, 17).
How many solutions are in the set 16x plus 2 - 8 equals 16x plus 24?
16x + 2 - 8 = 16x + 24 implies 16x - 6 = 16x + 24 subtracting 16x from both sides, this implies: -6 = 24 So the equation has no soultions.
What is the answer to x2-16x23?
what number do you add in the equation x2-16x=23
What is the vertex of the parabola of y equals -4x 2-16x-11?
f(x) = -4x2 - 16x - 11 a = -4, b = -16, c = -11 x-coordinate of the vertex = -b/2a = -(-16)/2(-4) = 16/-8 = -2 y-coordinate = f(-2) = -4(-2)2 -16(-2) - 11 = -16 + 32 - 11 = 5 vertex is (-2, 5)
X2 plus 16x plus 55 equals?
Assuming you wish to make this equation equal zero, for x2 + 16x + 55 = 0, x = -5.
What is the equation of a line that is parallel to 4y -16x equals 7 and that has a y-intercept of -3?
The parallel equation is: y = 4x-3
What type of equation is 4x2 -16x-y 210?
Without an equality sign the given terms can't be considered to be a quadratic equation.
