0
Considering a general quadratic equation y=ax^2 + bx + c, the x coordinate of the vertex is found from the formula x= -b/2a and the y coordinate is found from putting that x coordinate back into the original quadratic equation which in this case I am assuming is y= -2x^2 + 16x -15.
So, the x coordinate of the vertex is x=-16/(2*-2) = 4
To find the y coordinate we plug 4 back into y= -2x^2 + 16x -15 so we have y= -2 * 4^2 + 16*4 - 15. Following the order of operations we get y= -2 *16 + 64 - 15= 17
Therefore the vertex is at (4, 17).
Still curious? Ask our experts.
Chat with our AI personalities
Steve
Coach
EzraAdd your answer:
Earn +20 pts
What is the answer to POW 15 in IMP 2?
plot 4,-5 2,2 and 7,-5 on a graph than connect the vertex
How do you work out X x X - 16X plus 15 equals 0?
X2 - 16X + 15 = 0 (X - 1)(X - 15) = 0 So X -1 = 0 or X - 15 = 0 ie X = 1 or X = 15
2x2 plus 15 equals 11x?
2x2 + 15 = 11x ? Can be only for some values of x.2x2 + 15 = 11x subtract 11x to both sides2x2 - 11x + 15 = 0(2x - 5)(x - 3) = 02x - 5 = 0 or x - 3 = 0x = 5/2 or x = 3
What is the speed of a bobsled whose distance time graph indicates that it traveled 45 m in 15 s?
speed = distance/time speed = 45/15 = 3 m/s
What is the vertex angle of an isosceles triangle whose equal sides are 15 meters long if the area is 112.5 square meters?
Area = 0.5*a*b*sin(C) so 112.5 = 0.5*15*15*sin(c) 1 = sin(C) so C = pi/2 radians (or 90 degrees).
