The question contains an expression, not an equation and so there is no solution.
2x2+18x = 20 2x2+18x-20 = 0 x2+9x-10 = 0 (x+10)(x-1) = 0 x = -10 or x = 1
3x2 - 7x - 20 = (3x + 5)(x - 4)
To graph a parabola given the points (20, 70) and (0, -8) with the vertex in vertex form, first, identify the vertex, which is the midpoint of the x-coordinates of the points if they are symmetric. Assuming the vertex is at the point (h, k), you can use the vertex form of a parabola: (y = a(x - h)^2 + k). Substitute one of the given points into this equation to solve for the value of (a). Finally, plot the vertex and the points, and sketch the parabola opening either upwards or downwards based on the sign of (a).
An icosagon is a 20 sided polygon that has 20 vertices which is the plural of vertex
11x = 20x +1811x-20x=18x(11-20)=18-9x=18x=-2
2x2+18x = 20 2x2+18x-20 = 0 x2+9x-10 = 0 (x+10)(x-1) = 0 x = -10 or x = 1
3x2 - 7x - 20 = (3x + 5)(x - 4)
x=4 and x =7Improved Answer:-x2-18x-40 = (x+2)(x-20) when factored
3x2 -12x+24=-10x-20-3x2+6
An icosagon is a 20 sided polygon that has 20 vertices which is the plural of vertex
11x = 20x +1811x-20x=18x(11-20)=18-9x=18x=-2
3x2-7x-20 = (3x+5)(x-4) when factored
(3x + 5)(x - 4)
20
(3x - 5)(x + 4)
(x + 4)(3x - 5)
(3x-4)(x+5)