0
What else can I help you with?
What is the y value of the maximum y equals -x2 plus 6x-7?
20 and the vertex of the parabola is at (3, 20)
How many vertex in the icosagon?
An icosagon is a 20 sided polygon that has 20 vertices which is the plural of vertex
What is the slope and y-intercept and x-intercept of y equals -2 over 5x plus 20?
Slope= -2/5 y-intercept is 20 x-intercept is 50
What is the vertex to -5x2 plus 20x-13?
-5x2 + 20x - 13 describes a parabola, and you can find it's vertex in various ways. To find it using calculus, you can simply take it's derivative and solve for 0: f(x) = -5x2 + 20x - 13 f'(x) = -10x + 20 Let f'(x) = 0, then: 0 = -10x + 20 x = 2 Then simply plug the x value into the original equation: f(x) = -5 * 22 + 20 * 2 - 13 = -20 + 40 - 13 = 7 So the vertex of this parabola is at the point (2, 7). To solve it using strictly algebra, you can do it by expressing it as a value of y, and then rearranging accordingly: y = -5x2 + 20x - 13 y = -5(x2 - 4x) - 13 y = -5(x2 - 4x + 4 - 4) - 13 y = -5(x2 - 4x + 4) + 20 - 13 y = -5(x - 2)2 + 7 From which we can see that the vertex happens at the point (2, 7)
What is the x and y intercepts for 5x plus 2y equals 20?
The x intercept is the point where y = 0, the y intercept is the point where x =0: For the x intercept: 5x + 2y = 20, but y = 0 => 5x + 0 = 20 => x = 20/5 = 4. So the x intercept is at (4, 0). For the y intercept: 5x + 2y = 20, but x = 0 [The rest of the calculation is left as an exercise for the reader.]
What is the y value of the maximum y equals -x2 plus 6x-7?
20 and the vertex of the parabola is at (3, 20)
How many vertex in the icosagon?
An icosagon is a 20 sided polygon that has 20 vertices which is the plural of vertex
What is the slope and y-intercept and x-intercept of y equals -2 over 5x plus 20?
Slope= -2/5 y-intercept is 20 x-intercept is 50
What is the vertex to -5x2 plus 20x-13?
-5x2 + 20x - 13 describes a parabola, and you can find it's vertex in various ways. To find it using calculus, you can simply take it's derivative and solve for 0: f(x) = -5x2 + 20x - 13 f'(x) = -10x + 20 Let f'(x) = 0, then: 0 = -10x + 20 x = 2 Then simply plug the x value into the original equation: f(x) = -5 * 22 + 20 * 2 - 13 = -20 + 40 - 13 = 7 So the vertex of this parabola is at the point (2, 7). To solve it using strictly algebra, you can do it by expressing it as a value of y, and then rearranging accordingly: y = -5x2 + 20x - 13 y = -5(x2 - 4x) - 13 y = -5(x2 - 4x + 4 - 4) - 13 y = -5(x2 - 4x + 4) + 20 - 13 y = -5(x - 2)2 + 7 From which we can see that the vertex happens at the point (2, 7)
What is the x-intercept of the line given by the equation x- 4y20?
Assuming that you meant "x - 4y = 20", the x-intercept is x=20, and the y-intercept is y=-5.
How many faces edges and vertex does a dodecahedron have?
Dodecahedrons are a shape with 12 faces, 30 edges and 20 vertices.
How do you find x and y intercepts to this 4x -20?
24
What is the x- and y-intercepts of the line 4x-y equals 20?
-16
What is the x and y intercepts for 5x plus 2y equals 20?
The x intercept is the point where y = 0, the y intercept is the point where x =0: For the x intercept: 5x + 2y = 20, but y = 0 => 5x + 0 = 20 => x = 20/5 = 4. So the x intercept is at (4, 0). For the y intercept: 5x + 2y = 20, but x = 0 [The rest of the calculation is left as an exercise for the reader.]
What is the x intercept of 5x - 2y 20?
Assuming you meant 5x-2y=20... 5x - 2(0) = 20 5x = 20 x = 4 X-intercept is 4
How many triangle can you get out of a vertex of a hexagon?
20
How do you find the x and y intercept of -5x plus 10y equals 20?
Basically, the x-intercept is what x equals when y=0, and the y-intercept is what y equals when x=0. To find the x intercept, set y equal to 0. -5x+10(0)=20 -5x+0=20 -5x=20 divide both sides by -5 x=-4 so the x intercept is (-4,0) To find the y intercept, set x equal to 0. -5(0)+10y=20 0+10y=20 10y=20 divide both sides by 10 y=2 so the y intercept is (0,2)
