0
To find the equation of the parabola, we can use the vertex form, which is (y = a(x - h)^2 + k), where ((h, k)) is the vertex. Substituting the vertex ((-2, -20)), the equation becomes (y = a(x + 2)^2 - 20). Using the intercept ((0, -12)) to find (a), we substitute (x = 0) and (y = -12), resulting in (-12 = a(0 + 2)^2 - 20). Solving for (a) gives (a = 2), leading to the final equation (y = 2(x + 2)^2 - 20).
What else can I help you with?
How do you graph a parabola with these points (20)(70)(0-8) and vertex in vertex form?
To graph a parabola given the points (20, 70) and (0, -8) with the vertex in vertex form, first, identify the vertex, which is the midpoint of the x-coordinates of the points if they are symmetric. Assuming the vertex is at the point (h, k), you can use the vertex form of a parabola: (y = a(x - h)^2 + k). Substitute one of the given points into this equation to solve for the value of (a). Finally, plot the vertex and the points, and sketch the parabola opening either upwards or downwards based on the sign of (a).
What is the y value of the maximum y equals -x2 plus 6x-7?
20 and the vertex of the parabola is at (3, 20)
How many vertex in the icosagon?
An icosagon is a 20 sided polygon that has 20 vertices which is the plural of vertex
What is the slope and y-intercept and x-intercept of y equals -2 over 5x plus 20?
Slope= -2/5 y-intercept is 20 x-intercept is 50
What are the intercepts of -3x 5y-2z60?
To find the intercepts of the equation (-3x + 5y - 2z = 60), we can set two variables to zero and solve for the third. x-intercept: Set (y = 0) and (z = 0): (-3x = 60 \Rightarrow x = -20) (intercept at ((-20, 0, 0))). y-intercept: Set (x = 0) and (z = 0): (5y = 60 \Rightarrow y = 12) (intercept at ((0, 12, 0))). z-intercept: Set (x = 0) and (y = 0): (-2z = 60 \Rightarrow z = -30) (intercept at ((0, 0, -30))). Thus, the intercepts are ((-20, 0, 0)), ((0, 12, 0)), and ((0, 0, -30)).
How do you graph a parabola with these points (20)(70)(0-8) and vertex in vertex form?
To graph a parabola given the points (20, 70) and (0, -8) with the vertex in vertex form, first, identify the vertex, which is the midpoint of the x-coordinates of the points if they are symmetric. Assuming the vertex is at the point (h, k), you can use the vertex form of a parabola: (y = a(x - h)^2 + k). Substitute one of the given points into this equation to solve for the value of (a). Finally, plot the vertex and the points, and sketch the parabola opening either upwards or downwards based on the sign of (a).
What is the y value of the maximum y equals -x2 plus 6x-7?
20 and the vertex of the parabola is at (3, 20)
How many vertex in the icosagon?
An icosagon is a 20 sided polygon that has 20 vertices which is the plural of vertex
What is the slope and y-intercept and x-intercept of y equals -2 over 5x plus 20?
Slope= -2/5 y-intercept is 20 x-intercept is 50
What are the intercepts of -3x 5y-2z60?
To find the intercepts of the equation (-3x + 5y - 2z = 60), we can set two variables to zero and solve for the third. x-intercept: Set (y = 0) and (z = 0): (-3x = 60 \Rightarrow x = -20) (intercept at ((-20, 0, 0))). y-intercept: Set (x = 0) and (z = 0): (5y = 60 \Rightarrow y = 12) (intercept at ((0, 12, 0))). z-intercept: Set (x = 0) and (y = 0): (-2z = 60 \Rightarrow z = -30) (intercept at ((0, 0, -30))). Thus, the intercepts are ((-20, 0, 0)), ((0, 12, 0)), and ((0, 0, -30)).
What is the vertex to -5x2 plus 20x-13?
-5x2 + 20x - 13 describes a parabola, and you can find it's vertex in various ways. To find it using calculus, you can simply take it's derivative and solve for 0: f(x) = -5x2 + 20x - 13 f'(x) = -10x + 20 Let f'(x) = 0, then: 0 = -10x + 20 x = 2 Then simply plug the x value into the original equation: f(x) = -5 * 22 + 20 * 2 - 13 = -20 + 40 - 13 = 7 So the vertex of this parabola is at the point (2, 7). To solve it using strictly algebra, you can do it by expressing it as a value of y, and then rearranging accordingly: y = -5x2 + 20x - 13 y = -5(x2 - 4x) - 13 y = -5(x2 - 4x + 4 - 4) - 13 y = -5(x2 - 4x + 4) + 20 - 13 y = -5(x - 2)2 + 7 From which we can see that the vertex happens at the point (2, 7)
What is the x-intercept of the line given by the equation x- 4y20?
Assuming that you meant "x - 4y = 20", the x-intercept is x=20, and the y-intercept is y=-5.
How many faces edges and vertex does a dodecahedron have?
Dodecahedrons are a shape with 12 faces, 30 edges and 20 vertices.
How do you find x and y intercepts to this 4x -20?
24
What is the x- and y-intercepts of the line 4x-y equals 20?
-16
What is the x and y intercepts for 5x plus 2y equals 20?
The x intercept is the point where y = 0, the y intercept is the point where x =0: For the x intercept: 5x + 2y = 20, but y = 0 => 5x + 0 = 20 => x = 20/5 = 4. So the x intercept is at (4, 0). For the y intercept: 5x + 2y = 20, but x = 0 [The rest of the calculation is left as an exercise for the reader.]
What is the x intercept of 5x - 2y 20?
Assuming you meant 5x-2y=20... 5x - 2(0) = 20 5x = 20 x = 4 X-intercept is 4
