8x2 + 16x + 8 = 0
the roots are 1, - 1/3, - 3 1/2 and 3 1/2
8x2+6x-35 = (2x+5)(4x-7) when factored
x=5
x(x+3)(x+5)
What are the factors? 2x3 - 8x2 + 6x = 2x(x - 1)(x - 3).
2x3 + 8x2 + 3x + 12 = (2x3 + 8x2) + (3x + 12) = 2x2(x + 4) + 3(x + 4) = (x + 4)(2x2 + 3) Since you have asked this question I am assuming that you are not yet at a level where you might want (2x2 + 3) factorised into its imaginary factors.
8x2 + 16x + 8 = 0
the roots are 1, - 1/3, - 3 1/2 and 3 1/2
8x2 + 15 + 26x = 8x2 + 26x + 15 = 8x2 + 20x + 6x + 15 = 4x(2x + 5) + 3(2x + 5) = (2x + 5)(4x + 3)
7Improved Answer:8x2-18x+9 = (4x-3)(2x-3)
8x2+6x-35 = (2x+5)(4x-7) when factored
(2x + 1)(4x + 7)
x=5
8x2+6x-35 = (4x-7)(2x+5) when factored
-8(x - 7y)(x + 2y)
x(x+3)(x+5)