Volume = pi*22*7 = 28pi cubic feet.
If 2 feet is its diameter then:- Volume = 1/3*pi*12*7 = 7.33 cubic feet to 2 decimal places
There is 2 ft x 2ft x 2ft hole in the ground. To find the volume of the hole we multiply length x width x height of the object.So 2 x 2 x 2 = 8ft³There is 8ft³ of dirt in a 2ft x 2ft x 2ft hole.Another View:There is 8 cubic feet of air in the hole, but no dirt.
In terms of an oblong: 6in x 1ft x 28000ft 1ft x 1ft x 14000ft 1ft x 2ft x 7000ft 2ft x 2ft x 3500ft 20ft x 20ft x 35ft The above it not exhaustive - any three lengths that multiply together to create 14000cu ft will work. Other three dimensional shapes are equally possibly, eg pyramids (volume = 1/3 x base_area x height), cylinders (volume = {pi} x radius_base2 x height), as long as their volume is 14000cu ft.
Yes, 2 ft radius is 4 pi circumference which is about 12-and-a-half feet
A rectangular prism whose edges measure 3 ft 3 ft and 2ft has a volume of 18 cubic feet.
The answer for that is 48ft^3
A = 12.566 square feet.
If 2 feet is its diameter then:- Volume = 1/3*pi*12*7 = 7.33 cubic feet to 2 decimal places
It will require a minimum of three square feet of floor space.
2ft by 2ft by 5ft is a possibility
60 by 3 by 2 =360
There is 2 ft x 2ft x 2ft hole in the ground. To find the volume of the hole we multiply length x width x height of the object.So 2 x 2 x 2 = 8ft³There is 8ft³ of dirt in a 2ft x 2ft x 2ft hole.Another View:There is 8 cubic feet of air in the hole, but no dirt.
The volume of a cylinder isequal to the product of the area of a base and the altitude. The area of the base is (pi)d2/4=3.14 X (2ft)2/4 =3.14(ft)2 and the volume, V is V=3.14(ft)2 X 22ft = 69.08ft3
Volume is 30 cubic feet.
The Formula Would Look Like This...Volume/Height *Width...60Ft3in divided By 2Ft times 3Ft. I'm Prob In Your Class.
9feet
In terms of an oblong: 6in x 1ft x 28000ft 1ft x 1ft x 14000ft 1ft x 2ft x 7000ft 2ft x 2ft x 3500ft 20ft x 20ft x 35ft The above it not exhaustive - any three lengths that multiply together to create 14000cu ft will work. Other three dimensional shapes are equally possibly, eg pyramids (volume = 1/3 x base_area x height), cylinders (volume = {pi} x radius_base2 x height), as long as their volume is 14000cu ft.