If its in the shape of a rectangular block, just multiply length x width x height.
To find the volume of the salt crystal, multiply its dimensions together: [ \text{Volume} = 2.44 \times 10^{-2} , \text{m} \times 1.4 \times 10^{-3} , \text{m} \times 8.4 \times 10^{-3} , \text{m} ] Calculating this gives: [ \text{Volume} = 2.44 \times 1.4 \times 8.4 \times 10^{-8} , \text{m}^3 \approx 2.88 \times 10^{-7} , \text{m}^3 ] Thus, the volume of the salt crystal is approximately ( 2.88 \times 10^{-7} , \text{m}^3 ).
If they are mathematical geometric you can use geometry or calculus.If they are not, but are insoluble, you can immerse them in a suitable fluid and measure the volume of the fluid that is displaced. That method will not work for a large salt crystal, though!If they are mathematical geometric you can use geometry or calculus.If they are not, but are insoluble, you can immerse them in a suitable fluid and measure the volume of the fluid that is displaced. That method will not work for a large salt crystal, though!If they are mathematical geometric you can use geometry or calculus.If they are not, but are insoluble, you can immerse them in a suitable fluid and measure the volume of the fluid that is displaced. That method will not work for a large salt crystal, though!If they are mathematical geometric you can use geometry or calculus.If they are not, but are insoluble, you can immerse them in a suitable fluid and measure the volume of the fluid that is displaced. That method will not work for a large salt crystal, though!
Assuming the first measure is also in metres, the answer is 28.69*10-8 m3= 2.87*10-7 m3 or 0.28 cm3.
No.
1300 mg of salt is equivalent to 1.3 grams. In terms of volume, it roughly translates to about 0.5 teaspoons of table salt, as salt's density can vary slightly based on its form (e.g., granulated, coarse). This measurement is significant in dietary contexts, as it represents a portion of the recommended daily sodium intake.
2.9 x 10-7 m -3
2.87x10-7 m3
This depends on: volume of water, temperature of water, stirring, crystal dimensions, presence of other substances etc.
The volume of the salt crystal is calculated by multiplying the three dimensions together: V = (2.44 x 10^-2 m) * (1.4 x 10^-3 m) * (8.4 x 10^-3 m) = 2.85 x 10^-7 m^3.
2,44.10-2 x 1,4.10-3 x 8,4.10-3 = 2,87 mm3
If they are mathematical geometric you can use geometry or calculus.If they are not, but are insoluble, you can immerse them in a suitable fluid and measure the volume of the fluid that is displaced. That method will not work for a large salt crystal, though!If they are mathematical geometric you can use geometry or calculus.If they are not, but are insoluble, you can immerse them in a suitable fluid and measure the volume of the fluid that is displaced. That method will not work for a large salt crystal, though!If they are mathematical geometric you can use geometry or calculus.If they are not, but are insoluble, you can immerse them in a suitable fluid and measure the volume of the fluid that is displaced. That method will not work for a large salt crystal, though!If they are mathematical geometric you can use geometry or calculus.If they are not, but are insoluble, you can immerse them in a suitable fluid and measure the volume of the fluid that is displaced. That method will not work for a large salt crystal, though!
Assuming the first measure is also in metres, the answer is 28.69*10-8 m3= 2.87*10-7 m3 or 0.28 cm3.
It depends on the experiment. In one particular experiment, using the technique of measuring volume as a means of counting will work. Think of measuring volume; a tablespoon of sugar or salt. When measuring the volume of it, we are measuring how much space it takes up. This can also be a means of counting because once the molar mass of each element is accounted for, the number of moles (counting!) can be calculated.
The crystal is broken.
salt crystal is a pure substance hope this helps xx
Yes. Salt is a crystalline substance. The ions in the compound form a crystal lattice.
salt