It is not possible to answer the question since there is no recognised measurement called milliequivalents.
yes, since 1000 mg equals 1 gram
this question is not hard to answer, but it does require that one make some assumptions. The simplest answer assumes that the 20% salt solution refers to per cent by mass. Thus: a 20% salt solution is one which contains 20 mg salt for every 100 mg solution where the solution consists of a mixture of 20 mg salt plus 80 mg water. A 35% salt solution would contain 35 mg salt for every 65 mg water. Now, assuming that all the water in 18 mg of a 20% salt solution remains in the final solution we see that 18 mg salt solution x 20 mg salt/100 mg salt solution gives 3.6 mg of salt; thus, there are 18 mg total solution - 3.6 mg salt = 14.4 mg water. So the final salt solution must be one that contains 14.4 mg water and enough salt to make it 35% salt by mass. Mathematically, this is written as Z mg salt/(Z mg + 14.4 mg water) = 35/100 This gives Z = 0.35*(Z + 14.4) or Z = 0.35*Z + 0.35*14.4 which is same as Z = 0.35*Z + 5.04 and 0.65*Z = 5.04 so Z = 5.04/0.65 = 7.75 mg total salt needed. We started with 3.6 mg salt, so we must add 7.75 -3.6 = 4.15 mg salt Check: 7.75 mg salt/(7.75 mg salt + 14.4 mg water) = 0.35 or 35% There you go! --assuming that much salt dissolves that amount of water!
1000 mcg equals 1 mg.
680 mg
There are approximately 0.045 ounces in 1300 mg.
1300 mg = 0.04586 ounces
It is not possible to answer the question since there is no recognised measurement called milliequivalents.
Approximately 1.5 teaspoons of table salt contain 360 mg of sodium.
A grain is a unit of measurement in medicine. A one half grain equals 30 mgs as part of the apothecaries system
yes, since 1000 mg equals 1 gram
mL is a volumetric measurement and mg is a mass measurement. You must know the density of the material being measured in question to know the answer, which would be volume=mass/density
1300
That is 260 teaspoons.
1/4 teaspoon salt = 600 mg sodium 1/2 teaspoon salt = 1,200 mg sodium 3/4 teaspoon salt = 1,800 mg sodium 1 teaspoon salt = 2,300 mg sodium
one gram equals 1,ooo mg's
this question is not hard to answer, but it does require that one make some assumptions. The simplest answer assumes that the 20% salt solution refers to per cent by mass. Thus: a 20% salt solution is one which contains 20 mg salt for every 100 mg solution where the solution consists of a mixture of 20 mg salt plus 80 mg water. A 35% salt solution would contain 35 mg salt for every 65 mg water. Now, assuming that all the water in 18 mg of a 20% salt solution remains in the final solution we see that 18 mg salt solution x 20 mg salt/100 mg salt solution gives 3.6 mg of salt; thus, there are 18 mg total solution - 3.6 mg salt = 14.4 mg water. So the final salt solution must be one that contains 14.4 mg water and enough salt to make it 35% salt by mass. Mathematically, this is written as Z mg salt/(Z mg + 14.4 mg water) = 35/100 This gives Z = 0.35*(Z + 14.4) or Z = 0.35*Z + 0.35*14.4 which is same as Z = 0.35*Z + 5.04 and 0.65*Z = 5.04 so Z = 5.04/0.65 = 7.75 mg total salt needed. We started with 3.6 mg salt, so we must add 7.75 -3.6 = 4.15 mg salt Check: 7.75 mg salt/(7.75 mg salt + 14.4 mg water) = 0.35 or 35% There you go! --assuming that much salt dissolves that amount of water!