27.3 g is the mass of an aluminum sample with a volume of 10.0 cm3.
To find the volume of 5 grams of gold, you can use the density of gold, which is approximately 19.32 grams per cubic centimeter (g/cm³). Volume is calculated using the formula: Volume = Mass / Density. Therefore, the volume of 5 grams of gold is about 0.259 cubic centimeters (cm³) when you divide 5 grams by the density of 19.32 g/cm³.
volume =mass/ density volume = 55.932/8.92 = 6.27 cm3
To calculate the mass of a 600 ml sample of seawater, you need to know the density. If the density of seawater is approximately 1.025 g/ml, the mass can be calculated using the formula: mass = density × volume. Therefore, the mass of the seawater would be approximately 600 ml × 1.025 g/ml = 615 grams.
Assuming the gold nugget is solid and pure (unlikely in real life!) The volume of the nugget is 77.0 - 50.0 mL = 27.0 mL So density = mass/volume = 521/27.0 = 19.3 g per mL.
the answer is 0.051813471502590675129533678756 round to the nearest thousandths so it should be 0.052
The density of the sample can be calculated by dividing the mass of the sample (35.4g) by its volume (36.82 mL). Density = Mass/Volume Density = 35.4g / 36.82 mL Density = 0.962 g/mL
The volume of the sample whose mass is 20 g and density is 4 g/ml is 5 milliliters.
27.3 g is the mass of an aluminum sample with a volume of 10.0 cm3.
The density of gold is 19.32 g/cm^3. To find the volume of a 75 gram sample of gold, you divide the mass by the density: 75 g / 19.32 g/cm^3 ≈ 3.88 cm^3.
The density of the sample is calculated by dividing the mass (2.50 g) by the volume (1.7 mL). Density = mass/volume = 2.50 g / 1.7 mL = 1.47 g/mL.
The density of the sample is calculated by dividing the mass (77.0 g) by the volume (36 mL). The density of the sample would be 2.14 g/mL.
If the volumes of the samples of pyrite and gold are equal, you cannot directly determine the number of samples without knowing the specific mass or density of each material. Pyrite has a lower density (about 5 g/cm³) compared to gold (about 19.3 g/cm³), meaning that for the same volume, a sample of gold would weigh significantly more than a sample of pyrite. Therefore, while the volumes may be equal, the mass of gold will be greater than that of pyrite.
The density of the sample is calculated by dividing its mass by its volume. In this case, the mass is 1.25 g and the volume is 51 mL. Therefore, the density of the sample is 1.25 g/51 mL = 0.0245 g/mL.
To calculate the volume of a pure zinc sample, use the formula: volume = mass / density. The density of zinc is approximately 7.14 g/cm³. Therefore, the volume of the 4.50 g sample of zinc is calculated as follows: volume = 4.50 g / 7.14 g/cm³ ≈ 0.630 cm³.
The density of the sample of nickel is 8.86 g/mL. This is calculated by dividing the mass (3.1 g) by the volume (0.35 mL).
To find the volume of gold, first convert the mass of gold to grams (1 kg = 1000 g), so 15 kg = 15000 g. Then, use the mass density formula: density = mass/volume, rearrange it to find volume: volume = mass/density. Plug in the values: volume = 15000 g / 19.3 g/cm^3 = 777.2 cubic centimeters.