If you mean: % by MASS ( %m/m), it's quite easy to do (based on the 'Mass Conservation Law).Measure 10 gram of the 95%m/m original solution, this contains 95% of 10g = 9.5g SoluteThen add new solvent up to 95g final solution, so adding (95g - 10g =) 85 gram new solvent, then you'll get:9.5g Solute (in 10 g of original solution) in 95g (final) solution, thus 9.5g S / 95g = 10%m/mHowever if the meaning was: % by Volume ( %v/v) then calculation appears to get very complicated, but not impossible if you know at least the density values of all solutions (original 95%v/v and final 10%v/v) and of the solvent.(In that case mail me: JoppeDeQuint at answers dot com).DO NOT ever use: (orig. volume) + (added volume) = final volume.It's only a rule of thump, an approximation. This is because fluids can contract on mixing at dilution. There is no rule such as: conservation of volume.Your case: 10 ml + 85 ml (is not equal but) < 95 ml final solution.
seventy cubic feet
It is impossible to answer the question since there are no units given. Volume of 10 what? The density of gold is 19.3 gcm-3 which may imply that the volume is given in SI units, but that could be cubic metres, cubic centimetres or cubic micrometres.
Assuming the gold nugget is solid and pure (unlikely in real life!) The volume of the nugget is 77.0 - 50.0 mL = 27.0 mL So density = mass/volume = 521/27.0 = 19.3 g per mL.
193g
It is 0.419 cups.
It depends on the context. In terms of everyday objects, 95g could be considered light, but in terms of certain small electronic devices or accessories, it could be considered heavy.
Just a tad under 1 cup
The volume increase will be equal to the volume of the gold submerged in the water. The volume of the gold can be calculated by dividing its mass by its density (19.32 g/cm³ for gold). Submerging the gold in water will displace an equal volume of water, resulting in the measured volume increase.
To calculate the mass and volume of gold, we need to know either the mass or the volume specifically. Given the density of 19.3 g/cm3, if you have the volume of gold, you can calculate the mass by multiplying the volume by the density. If you know the mass, you can calculate the volume by dividing the mass by the density.
If you mean: % by MASS ( %m/m), it's quite easy to do (based on the 'Mass Conservation Law).Measure 10 gram of the 95%m/m original solution, this contains 95% of 10g = 9.5g SoluteThen add new solvent up to 95g final solution, so adding (95g - 10g =) 85 gram new solvent, then you'll get:9.5g Solute (in 10 g of original solution) in 95g (final) solution, thus 9.5g S / 95g = 10%m/mHowever if the meaning was: % by Volume ( %v/v) then calculation appears to get very complicated, but not impossible if you know at least the density values of all solutions (original 95%v/v and final 10%v/v) and of the solvent.(In that case mail me: JoppeDeQuint at answers dot com).DO NOT ever use: (orig. volume) + (added volume) = final volume.It's only a rule of thump, an approximation. This is because fluids can contract on mixing at dilution. There is no rule such as: conservation of volume.Your case: 10 ml + 85 ml (is not equal but) < 95 ml final solution.
Gold is heavier than silver. Gold has a higher density than silver, which means that a specific volume of gold will weigh more than the same volume of silver.
The specific volume of gold is around 0.001 m³/kg at room temperature and pressure. This means that 1 kilogram of gold occupies 0.001 cubic meters of space.
The volume of the gold nugget can be calculated by finding the difference in volume before and after adding the nugget. The volume of the gold nugget is 225 mL (final volume) - 85 mL (initial volume) = 140 mL.
Gold is heavier than silver. Gold has a higher density than silver, meaning that a given volume of gold weighs more than the same volume of silver.
Irdk. :)
Measure the gold, take the volume of the gold, then divide mass over volume to give you the density of gold if it was the same as gold density then it is right other wise that ring is doggy