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Answer #2:
I believe you want the volume of the shell ... the material between the
inside and outside diameters ... whereas the first answer, above, gave you
the volume of the hole in the middle of everything. Here's my take on it:
-- Volume of a sphere is 4/3 pi R3
-- Volume enclosed by the outer radius is 4/3 pi (2)3
-- Volume enclosed by the inner radius is 4/3 pi (1)3
-- Volume of the material between them is
4/3 pi (23 - 13) = 4/3 pi x 7 =
28/3 pi = 29.32 m3. (rounded)
The volume of a spherical shell is equal to the difference between the volume of a sphere with a radius of 2 m and a volume of a sphere with a radius of 1 meter:
V= 29,321531433504736892318004910609 м3
A sphere, of radius a = 11.4 cm and charge q = 5.00 × 10 − 6 C uniformly distributed throughout its volume, is concentric with a spherical conducting shell of inner radius b = 26.2 cm and outer radius c = 28.2 cm . This shell has a net charge of -q. visit our page : grandarchinex.co.in
If the Smaller inner radius is r, Larger inner radius is R, and the Length of the pipe is L then Vol = 1/3*pi*L*(R2 + Rr + r2)
pi(r2)of inner minus pi(r2) of outer. multiply height= volume or you could drop it in a beaker and see how much water was displaced
Consider the volume of the pipe as the difference in the volume of two cylinders, one containing the whole pipe and the other the empty space inside. Use the formula for the volume of a cylinder : Pi*r*r*h. Find the volume of the first cylinder with the larger radius and subtract from it that of the cylinder with the smaller radius. The height (or length) is the same for both volume calculations. The result of subtracting these is the volume occupied by the pipe.
Take the inside diameter, from inner edge to opposite inner edge and going through the middle. Divide this by two to give you an inside radius. Multiply this by itself to give the radius squared, then multiply this by Pi to give inside area. Finally, multiply this by the length of the pipe to give the volume.
Surface area of a sphere = 4*pi*radius2 For a spherical shell, surface area = surface area of outer sphere - surface area of inner sphere = 4*pi*(outer radius)2 - 4*pi*(inner radius)2 = 4*pi*[ (outer radius)2 - (inner radius)2 ]
A sphere, of radius a = 11.4 cm and charge q = 5.00 × 10 − 6 C uniformly distributed throughout its volume, is concentric with a spherical conducting shell of inner radius b = 26.2 cm and outer radius c = 28.2 cm . This shell has a net charge of -q. visit our page : grandarchinex.co.in
The inner planets have a spherical shape. In fact all planets are more or less spherical.
The volume of water in one meter of a 22mm-diameter pipe is: about 0.1 US gallons.
If the Smaller inner radius is r, Larger inner radius is R, and the Length of the pipe is L then Vol = 1/3*pi*L*(R2 + Rr + r2)
pi(r2)of inner minus pi(r2) of outer. multiply height= volume or you could drop it in a beaker and see how much water was displaced
Consider the volume of the pipe as the difference in the volume of two cylinders, one containing the whole pipe and the other the empty space inside. Use the formula for the volume of a cylinder : Pi*r*r*h. Find the volume of the first cylinder with the larger radius and subtract from it that of the cylinder with the smaller radius. The height (or length) is the same for both volume calculations. The result of subtracting these is the volume occupied by the pipe.
dV=E.ds -> C=Q/V=Q/QK[1/r1 - 1/r2] = 4pi epsilon_o [1/r1 - 1/r2]
Take the inside diameter, from inner edge to opposite inner edge and going through the middle. Divide this by two to give you an inside radius. Multiply this by itself to give the radius squared, then multiply this by Pi to give inside area. Finally, multiply this by the length of the pipe to give the volume.
Outer volume = pi*142*40 cm3 Inner volume = pi*122*40 cm3 Volume of steel = Outer volume - Inner volume = pi*(142 - 122)*40 cm3 = pi*52*40 = 6535 cm3 approx.
The inner planets have a spherical shape. In fact all planets are more or less spherical.
It is not possible to find the volume from the two radii. That will only give the surface area of the disk that it forms. To find the volume yYou also need the thickness of .